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navik [9.2K]
3 years ago
15

Ethylene glycol (antifreeze) has a density of 1.11 g/cm3. What is the mass in grams of 387 mL of ethylene glycol?

Chemistry
1 answer:
olga2289 [7]3 years ago
6 0
Cm^3 = mL

1.11 g/cm^3 = 1.11 g/mL

Density (g/mL) multiplied by volume (mL) will give us the mass (g)

1.11 g/mL * 387 mL = 429.57 g

And since we have 3 significant figures, we have 430. g.
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Below!

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2032533 \sq22222rt[2]{?}

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An certain element Y has two naturally occurring isotopes, 6Y (isotopic mass = 6.015123 amu) and 7Y (isotopic mass = 7.016005 am
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The percentage abundance of  6Y is 0.102.

An Isotope refers to two or more atoms that has the same atomic number but different mass  numbers.

We have been informed from the question that the atomic mass of the element is 6.9412 amu.

Let the abundance of isotope 6Y be x

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Hence;

6.9412 = 6.015123x + 7.016005(1 - x)

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