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3 years ago

Whats the cubed root of 39 times the cubed root of 39 times the cubed root of 39

Mathematics

1 answer:

Nataly [62]3 years ago

6 0

It's equal to 39 since that number multiplied by itself three times equals 39. i hope it makes sense.

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the probability that we encounter a green light at the corner of college and main is 0.35, a yellow light 0.04, and a red light

Ostrovityanka [42]

Answer:

21% probability you will hit a green light on monday and a red light on tuesday

Step-by-step explanation:

When two events, A and B, are independent, we have that:

$P(A \cap B) = P(A) \times P(B)$

In this problem, we have that:

Event A: Green light on monday.

Event B: Red light on tuesday.

The probability that we encounter a green light at the corner of college and main is 0.35

This means that $P(A) = 0.35$

The probability that we encounter a red light is 0.61:

This means that $P(B) = 0.61$

These events are independent, that is, the light color on Tuesday is independent of the color on Monday. So

$P(A \cap B) = P(A) \times P(B) = 0.35 \times 0.6 = 0.21$

21% probability you will hit a green light on monday and a red light on tuesday

8 0

3 years ago

Helppp me plsssssssss<br><br>

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

Please help and thank you so much in advanced

sdas [7]

x=18

y=-6

To find the x intercept, you would substitute the y with 0 and then solve for x.

To find the y intercept, you would substitute the x with 0 and solve for y.

Hope this helps braniliest please!

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Klio2033 [76]

Answer: The number should be 6

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2 years ago

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Oduvanchick [21]

You attended school for 16 hours in a month.

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