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Lelu [443]
3 years ago
9

Estimate the quotient by rounding the expression to relate to a one-digit fact. Explain your thinking in the space below. 432 ÷

73 ≈ ___ *
Mathematics
2 answers:
muminat3 years ago
7 0
It would be 5.9,, I looked ok my calculator
blsea [12.9K]3 years ago
6 0

Answer:

5.9..... there are a bunch of numbers after that but you would round it to 6.0

Step-by-step explanation:

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If a function is odd, then which statement is true?
jolli1 [7]
By definition, a function is odd if f(-x) = -f(x) for all x in the domain. The answer is choice C

Side note: a function is even if f(-x) = f(x) for all x in the domain
4 0
2 years ago
If a spring stretches 6 meters when a 7-kilogram weight is attached to it, how much will it stretch when a 42-kilogram weight is
Zinaida [17]

Answer:

Step-by-step explanation:

 This is a simple proportion problems.

7 kilogram weight attache to a spring stretches  = 6 meters

 1 kilogram would stretch                                       =  6/7 m

Therefore 42 kilograms would  stretch                  = (6/7 x 42)meters

                                                                                 =  36 meters.

                                                                         

 

8 0
3 years ago
What is the equivalent expression for 8w - 16?
Maslowich

Answer:

8(w - 2)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
2xy-(x-(+3) when x =-3 and y=1​
RSB [31]
0 should be the answer
6 0
2 years ago
Given that f(x) = x + 3<br> a) Find f(2)
Nataly_w [17]

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

In the above question, it is given that :

\qquad \sf  \boxed{ \sf f(x) =  \frac{x + 3}{2} }

A.) Find f(2) :

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{2 + 3}{2}

\qquad \sf  \dashrightarrow \: f(2) =  \dfrac{5}{2}

or

\qquad \sf  \dashrightarrow \: f(2) = 0.5

B.) Find { \sf {f}^{-1}(x) } :

\qquad \sf  \dashrightarrow \: let \: y = f (x)

so, we can write it as :

\qquad \sf  \dashrightarrow \: y =  \dfrac{x + 3}{2}

\qquad \sf  \dashrightarrow \: 2y = x + 3

\qquad \sf  \dashrightarrow \: x = 2y - 3

Now, put x = { \sf {f}^{-1}(x) }, and y = x and we will get our required inverse function ~

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(x) = 2x- 3

C.) Find { \sf {f}^{-1}(12) } :

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 2(12)- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 36- 3

\qquad \sf  \dashrightarrow \: f {}^{ - 1}(12) = 33

7 0
10 months ago
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