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3 years ago

Which operation should you perform after (9 + 6) in the expression

Mathematics

2 answers:

never [62]3 years ago

8 0

Answer:

$10 \times 2$

Step-by-step explanation:

According to BODMAS theorem,

After the brackets you have to the multiplication..

Can I have the brainliest please?

slega [8]3 years ago

3 0

10 x 2

If you follow PEMDAS what comes after the P (for parenthesis) is M (for multiplication). Hope this helps!

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Select the procedure that can be used to show the converse of the Pythagorean theorem using side lengths chosen from 6 cm, 8 cm,

finlep [7]

Answer:

I think A

Step-by-step explanation:

With the equasions shown A makes the most sense

3 0

2 years ago

A detergent company periodically tests its products for variations in the fill weight. To do this, the company uses x-bar and R

maw [93]

Answer:

10.9361

Step-by-step explanation:

The lower control limit for xbar chart is

xdoublebar-A2(Rbar)

We are given that A2=0.308.

xdoublebar=sumxbar/k

Rbar=sumR/k

xbar R

5.8 0.42

6.1 0.38

16.02 0.08

15.95 0.15

16.12 0.42

6.18 0.23

5.87 0.36

16.2 0.4

Xdoublebar=(5.8+6.1+16.02+15.95+16.12+6.18+5.87+16.2)/8

Xdoublebar=88.24/8

Xdoublebar=11.03

Rbar=(0.42+0.38+0.08+0.15+0.42+0.23+0.36+0.4)/8

Rbar=2.44/8

Rbar=0.305

The lower control limit for the x-bar chart is

LCL=xdoublebar-A2(Rbar)

LCL=11.03-0.308*0.305

LCL=11.03-0.0939

LCL=10.9361

8 0

3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

Which of the following is the coefficient in the algebraic expression 8x + z2

Olin [163]

Answer:

Step-by-step explanation:

Hope this is right! ;)

3 0

3 years ago

What is another way to say 345 centimeters?

Zolol [24]

100 centimeters is equal a meter so you can say 345 centimetres is the same as 3,45 metres

i hope i helped you somehow

7 0

3 years ago

Read 2 more answers