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3 years ago

10. Susan will take out a loan for $7500 to buy a used car. The simple

Mathematics

1 answer:

erastova [34]3 years ago

3 0

Okie so I can see you in the first place lol and queen and I are

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The record low temperature for a town is -13F. Yesterday, it was 6F. What is the difference between the absolute values of these

Keith_Richards [23]

Answer:

Step-by-step explanation:

We know that absolute values are the non negative equivalents to a negative. For instance, -8's absolute value is 8. In the question, you are being asked what the difference is. If we do a simple equation: 13 - 6 = 7, we get the answer.

5 0

2 years ago

Daniel borrowed $5000 from the bank for 2 years at 9% simple interest per annum. Calculate how much interest Daniel is charged.

RideAnS [48]

Answer:

Daniel is charged $900

Step-by-step explanation:

This is because 9 percent of 5000 is 450. Multiply 450x2 and get 900.

6 0

3 years ago

In a city the distance between the libary and the police station is 3 miles less than than the distance between the police stati

Mademuasel [1]

Answer:

8 miles

Step-by-step explanation:

Given

Represent the police station with P, Library with L; Fire station with F

The first statement can be represented as:

$L - P = P - F - 3$

The second can be represented as:

$L - P = 5$

Required

Determine the distance between the police station and the fire station (P - F)

$L - P = P - F - 3$ --- (1)

$L - P = 5$ --- (2)

Substitute 5 for L - P in (1)

$5 = P - F - 3$

Add 3 to both sides

$3 +5 = P - F - 3 + 3$

$3 +5 = P - F$

$8= P - F$

$P - F = 8$

5 0

3 years ago

Find the area of the circle whose equation is x2+y2=6x-8y

Semenov [28]

Answer:

Given that the equation of a circle is :

$\green{ \boxed{\boxed{\begin{array}{cc} {x}^{2} + {y}^{2} = 6x - 8y \\ = > {x}^{2} + {y}^{2} - 6x + 8y = 0 \\ = > {x}^{2} + {y}^{2} + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\ \\ \sf \: standard \: equation \: o f \: circle \: is : \\ {x}^{2} + {x}^{2} + 2gx + 2fy + c = 0 \\ \\ \sf \: by \: comparing \\ \\ g = - 3 \\ f = 4 \\ c = 0 \\ \\ \sf \: radius \: \: r = \sqrt{ {g}^{2} + {f}^{2} - c } \\ = \sqrt{ {( - 3)}^{2} + {4}^{2} - 0 } \\ = \sqrt{9 + 16} \\ = \sqrt{25} \\ = 5 \: unit \\ \\ \bf \: area \: = \pi {r}^{2} \\ = \pi \times {5}^{2} \\ =\pink{ 25\pi \: { unit }^{2} }\end{array}}}}$