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Answer is in the attachment.
Identity used :-
1) cosec² α = 1 + cot² α
Trigonometric Ratio :-
1) cot 30° = √3
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Reddam is an expensive school, right?
RainbowSalt2222 ☔
Answer: The greatest number of rows Li Na can plant is 9.
Step-by-step explanation:
Given: Li Na is going to plant 63 tomato plants and 81 rhubarb plants.
Li Na would like to plant the plants in rows where each row has the same number of tomato plants and each row has the same number of rhubarb plants.
To find the greatest number of rows Li Na can plant, we need to find the GCF of 63 and 81.
Since , 
Clearly, GCF(63,81)=9
Therefore, the greatest number of rows Li Na can plant is 9.
The answer is -3 !
Explanation:
Please give brainliest
Elimination Method

If we multiply the equation 3 by (-1) we obtain this:

If we add them we obtain 0, therefore there are infinite solutions. So, let's write it in terms of Z
1. Using the 3rd equation we can obtain X(Y,Z)

2. We can replace this value of X in the 1st and 2nd equations

3. If we simplify:

4. We can obtain Y from this two equations:

5. Now, we need to obtain X(Z). We can replace Y in X(Y,Z)

6. If we simplify, we obtain:

7. In conclusion, we obtain that
(X,Y,Z) =
When g(x) = -30, x = -10
To solve, make -30 equal to 2(x-5):
-30 = 2(x-5)
-30 = 2x -10
-20 = 2x
-10 = x