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algol [13]
3 years ago
13

Evaluate: 7 + 3 · 4 + 8 – 5

Mathematics
2 answers:
4vir4ik [10]3 years ago
7 0

Answer:

22

Step-by-step explanation:

shtirl [24]3 years ago
3 0

Answer:

22 :)

Step-by-step explanation:

PENDMAS

7 + 3 · 4 + 8 – 5

7+12+8-5

19+8-5

27-5

22

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A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
Ten Points For First To Answer Correctly
GalinKa [24]

Answer:

23/34

Step-by-step explanation:

This is guessing you only have fiction books.

6 0
3 years ago
Robert is accelerating a cart at the rate of 2.2 meters/second2. If the mass in the cart is doubled, and the net force is also d
Sindrei [870]
F = ma

the question said, F and M both are doubled ,so,

2F =2ma
but you can see the result is same !!

so acceleration doesn't change !! so final acceleration is also 2.2 !!
3 0
3 years ago
Answer answer please please
denpristay [2]

Answer: The answer is the first choice ( >)

Step-by-step explanation: 4.3 × 10⁶ = 4300000 . 12.1 × 10⁵ = 1210000 . So 4300000 is greater than 1210000 . HOPE IT HELPS YOU . PLEASE GIVE BRAINLIEST . THANKS .

7 0
2 years ago
2. Find the product (2x + 3)(3x - 2).
eimsori [14]

Answer:

6x² + 5x - 6

Step-by-step explanation:

Given

(2x + 3)(3x - 2)

Each term in the second factor is multiplied by each term in the first factor, that is

2x(3x - 2) + 3(3x - 2) ← distribute both parenthesis

= 6x² - 4x + 9x - 6 ← collect like terms

= 6x² + 5x - 6

6 0
3 years ago
Read 2 more answers
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