Answer:
The flash.
Step-by-step explanation:
He used to max out at Mach 1. Since crossover events are exceedingly rare, it is safe to assume that if you were comparing their speeds, the Flash is <u><em>consistently</em></u> faster than Quicksilver, though operationally speaking both could be consider comparable since their feats tend to be done at the same overall speed.
Answer:
m = 7
Step-by-step explanation:
2m + -4 = 10
Reorder the terms:
-4 + 2m = 10
Solving
-4 + 2m = 10
Solving for variable 'm'.
Move all terms containing m to the left, all other terms to the right.
Add '4' to each side of the equation.
-4 + 4 + 2m = 10 + 4
Combine like terms: -4 + 4 = 0
0 + 2m = 10 + 4
2m = 10 + 4
Combine like terms: 10 + 4 = 14
2m = 14
Divide each side by '2'.
m = 7
Simplifying
m = 7
Answer:
11.25
Step-by-step explanation:
13.79-x
Let x= 2.54
13.79-2.54
11.25
Answer:
The answer is below
Step-by-step explanation:
12 inches = 1 ft.
6 inches = 6 inches * (1 ft./12 inches) = 0.5 ft.
Therefore the diameter of the cast iron (D) = 6 inches = 0.5 ft.
The area of cast iron (A) = πD²/4 = π(0.5)²/4 = 0.196 ft²
The velocity (V) = 6 ft./s, the acceleration due to gravity (g) = 32.2 ft./s²
ε/D = 0.0004 ft./ 0.5 ft. = 0.0008
Using the moody chart, find the line ε/D = 0.0008 and determine the point of intersection with the vertical line R = 2.7 * 10⁵. Hence we get f = 0.02.
The head loss (h) is:

The pressure drop (Δp) is:
Δp = ρg
= 
A rectangle is considered a special case of a parallelogram because: Aparallelogram is a quadrilateral with 2 pairs of opposite, equal and parallel sides. Arectangle is a quadrilateral with 2 pairs of opposite, equal and parallel sides BUT ALSO forms right angles between adjacent sides.