The statement says, "Triangle ABC has vertices A(1,2), B(1,5), and C(4,2) and undergoes a transformation."
The question asked is to find the set of vertices that does not belong to the group. This means that an attachment is expected to be there. The absence of any attachment makes this question hard to answer. Maybe this helps answer you question.
Answer: Hello mate!
we know that p(x,y) means "Student x has taken class y"
and the used symbols are:
∃: this means "existence", you use this symbol to say that there exists at least one object that makes true the sentence.
∀: this means "for all", you use this symbol to say that the sentence is true for all the elements, then:
a) ∃x∃yP (x, y)
"exist at least one student x, that took at least one class y"
b) ∃x∀yP (x, y)
"exist at least one student x, that took all the classes y"
c) ∀x∃yP (x, y)
"every student x, took at least one class y"
d) ∃y∀xP (x, y)
"exist at least one class y, that has been taken by all the students x"
e) ∀y∃xP (x, y)
"for every class y, there is at least one student x that took the class"
f) ∀x∀yP (x, y)
"all the students x took all the classes y"
Best to take this in two parts.
1, find the factors of 36:
1 and 36
2 and 18
3 and 12
4 and 9
6 and 6
2, Now, using those, add the factors and see which add up to 15... in this case, that would be 12 and 3!
12in = 1 foot
3 feet = 1 yard
36in = 1 yd
36x2 = 72in/6=12x20 = 240 cents
$2.40
Answer:
f⁻¹(x) = ± √x-6
Step-by-step explanation:
f(x) = x² + 6
y = x² + 6
x = y² + 6 ... replace x and y
solve y: y² = x - 6
y (f⁻¹(x)) = ± √x-6
