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3 years ago

Describe what is being done in each step while solving the equation -2x + 6 +6x = 6 ( 2x -3 )

Mathematics

1 answer:

Serggg [28]3 years ago

5 0

-2x + 6 + 6x = 6 (2x - 3) this is the equation

-2x + 6 + 6x = 12x - 18 distributive property has been applied

4x + 6 = 12x - 18 like terms have been added

6 = 8x -18 4x has been subtracted from both sides

24 = 8x -18 has been added to both sides

3 = x 8 has been divided from both sides

I hope this helps! Let me know if I need to explain more or if I got something wrong. Have a nice day!

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3 years ago

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jarptica [38.1K]

Answer with explanation:

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--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

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3 years ago

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Shtirlitz [24]

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3 years ago

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erica [24]

Answer:

1.5 hours or 90 minutes

Step-by-step explanation:

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Sever21 [200]

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2 years ago