I believe it is Since the square root of 9 = 3 and the square root of 16 = 4 it is known the the square root of 12 is in between 3 and 4. Really hope this helps!
Step-by-step explanation:
a−(6a−(5a−8))
a-(6a-5a+8)
a-6a+5a-8
6a-6a-8
0-8
=-8
so the answer doesn't depend on a
Answer: 16p^8q^4r^8 The yellow one
Step-by-step explanation:
Step 1: Use Multiplication Distributive Property: (xy)^a = x^a y^a. So 4^2p^2(q^3)(r^4)^2
Step 2: Simplify 4^2 to 16. So 16p^2(q^3)^2(r^4)^2
Step 3: Use Power Rule: (x^a)^b=x^ab. So 16p^2q^6(r^4)^2
Step 4: Use Power Rule: (x^a)^b=x^ab. So the answer is 16p^2q^6r^8. The yellow one
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Yayyyy that’s the answer
