There are 6.022 × 10²³ atoms in 39.948 g of argon and 4.0026 g of helium.
Explanation:
39.945 g/mole is the molar mass of argon so 39.948 g of argon are equal to 1 mole of argon.
4.0026 g/mole is the molar mass of helium so 4.0026 g of helium are equal to 1 mole of helium.
We know that Avogadro's number tell us the number of particles in 1 mole of substance which is 6.022 × 10²³.
So in 39.948 g of argon and 4.0026 g of helium contains the same number of atoms, 6.022 × 10²³.
Learn more about:
Avogadro's number
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Boiling Point, Melting Point, Viscosity, Surface Tension. Decrease: Vapor Pressure.
Answer: 35.6 g/mol
Explanation: I guessed and got it correct
Answer:
The level of toxins in solutions
Answer:742 torr= approximately 0.976 atm
Explanation:
Since we know that one atm= 760 torr, we can compute the following calculation:
(742 torr/1)*(1atm/760torr)=0.976316 atm
Remember sig figs (3) to round it to 0.976 atm
*
=0.976316=0.976 atm
(torr cancels out and we're left with atm)
Hope this helps :)
