All categories

3 years ago

30,434 and 43,403 alike and difrente

1 answer:

7 0

They are alike because they have the same numbers in a different order. One is reversing the numbers of the original set. They are different because one number is larger in value while the other is lesser in value compared to each other.

You might be interested in

How much faster does nitrogen monoxide (NO) effuse in comparison to dinitrogen tetraoxide (N2O4)?

juin [17]

Answer:

N5O2

Explanation:

5 0

3 years ago

What is the velocity of a 0.5-kg ball that has a momentum of 3 kg.m/s?

maria [59]

Answer:

6m/s

Explanation:

Data obtained from the question include:

Mass = 0.5kg

Momentum = 3 kg.m/s

Velocity =.?

Momentum is simply the product of mass and velocity as shown by the equation below:

Momentum = Mass x Velocity

Velocity = Momentum /mass

Velocity = 3kg.m/s / 0.5kg

Velocity = 6m/s

Therefore, the velocity of the ball is 6m/s

3 0

3 years ago

The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C

Kay [80]

Answer: The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

For $_{17}^{35}\textrm{Cl}$ isotope:

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 35 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

For $_{17}^{37}\textrm{Cl}$ isotope:

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 37 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

$35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.775\times 100=77.5\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.775)=0.225\times 100=22.5\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

6 0

3 years ago

The table below gives the masses of two different subatomic particles found in an atom.

kap26 [50]

I think the subatomic particles that are paired with each of their corresponding name would be :
1. X , proton and z, electron

hope this helps

7 0

3 years ago

Read 2 more answers

Explain hydrogen dioxide

frozen [14]

Answer:

Two molecules of hydrogen combine with two molecules of oxygen to form hydrogen peroxide. Hence, its chemical formula is H2O2. It is the simplest peroxide (since it is a compound with an oxygen-oxygen single bond). Hydrogen peroxide has basic uses as an oxidizer, bleaching agent and antiseptic

4 0

3 years ago