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Ulleksa [173]
3 years ago
5

30,434 and 43,403 alike and difrente

Chemistry
1 answer:
Svetlanka [38]3 years ago
7 0
They are alike because they have the same numbers in a different order. One is reversing the numbers of the original set. They are different because one number is larger in value while the other is lesser in value compared to each other.
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juin [17]

Answer:

N5O2

Explanation:

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3 years ago
What is the velocity of a 0.5-kg ball<br> that has a momentum of 3 kg.m/s?
maria [59]

Answer:

6m/s

Explanation:

Data obtained from the question include:

Mass = 0.5kg

Momentum = 3 kg.m/s

Velocity =.?

Momentum is simply the product of mass and velocity as shown by the equation below:

Momentum = Mass x Velocity

Velocity = Momentum /mass

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3 0
3 years ago
The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C
Kay [80]

<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.775\times 100=77.5\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

6 0
3 years ago
The table below gives the masses of two different subatomic particles found in an atom.
kap26 [50]
I think the subatomic particles that are paired with each of their corresponding name would be :
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7 0
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Explain hydrogen dioxide​
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