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nadya68 [22]
3 years ago
10

If 2,035 cal of heat is added to a 500.0 g sample of water at 35.0°C, what is the final

Chemistry
1 answer:
Lynna [10]3 years ago
5 0

Answer:

39.1 °C

Explanation:

Recall the equation for specific heat:

q=mc \Delta T\\

Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.

You should know that the specific heat of water is 1 cal/g/C.

Using the information in the question:

2035=500(1)(T-35)\\2035=500T-17500\\500T=19535\\T=39.07

The final temperature is about 39.1 °C.

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