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3 years ago

What is Oxygen an

Chemistry

1 answer:

GalinKa [24]3 years ago

4 0

The answer is #2// gas

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In a titration experiment 12.5 ml of 0.500 m h2so4 neutralized 50.0 ml of naoh. the concentration of the naoh solution is ____.

s344n2d4d5 [400]

0.250 mol/L

Step 1. Write the chemical equation

H2SO4 + 2NaOH → Na2SO4 + 2H2O

Step 2. Calculate the moles of H2SO4

Moles of H2SO4 = 12.5 mL H2SO4 × (0.500 mmol H2SO4/1 mL H2SO4)

= 6.25 mmol H2SO4

Step 3. Calculate the moles of NaOH

Moles of NaOH = 6.25 mmol H2SO4 × (2 mmol NaOH/(1 mmol H2SO4)

= 12.5 mmol NaOH

Step 4. Calculate the concentration of the NaOH

[NaOH] = moles/litres = 12.5 mmol/50.0 mL = 0.250 mol/L

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3 years ago

To squeeze gas into a smaller space

Nadya [2.5K]

To squeeze a gas into a dmaller place is to compress it.

6 0

3 years ago

A solution contains 35 g of NaCl per 100 g of water at 25 ∘C. Is the solution unsaturated, saturated, or supersaturated?

MatroZZZ [7]

Answer:

Explanation:

5 0

3 years ago

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if you are a scientific or a inventor what do you want to discover or to invent relate to electrogmagnetism

puteri [66]

Answer:

Michal Faraday 19th century

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3 years ago

In 1983, a pilot miscalculated the fuel requirement for Air Canada Fight 143 from Montreal to Edmonton. Halfway through the flig

drek231 [11]

Answer:

27,397.23 L would be needed for a successful trip.

Explanation:

The problem gives us the density (ρ) of the fuel, by telling us that there are 803 g of fuel in 1 L, in which case:

ρ= $\frac{mass}{Volume}=\frac{803g}{1L} =803\frac{g}{L}$

The required mass of fuel is 2.2 * 10⁴ kg, we can convert this value into g:

2.2 * 10⁴ kg * $\frac{1000g}{1kg}$ = 2.2 * 10⁷ g

We calculate the required volume (V), using the mass and density:

$803 g/L = \frac{2.2*10^{7}g }{V} \\V=\frac{2.2*10^{7}g }{803g/L}\\ V=27397.26 L$

Thus 27,397.23 L would be needed for a successful trip.

5 0

3 years ago