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2 years ago

Yoo can somebody help me?

Mathematics

1 answer:

jok3333 [9.3K]2 years ago

4 0

Answer:

Step-by-step explanation:

Triangle 1 given: 100° , 17 yds, 30 yds

Triangle 2 given: 30 ,17,18

law of cosines: c^2 = a^2 + b^2 − 2ab cos(C)

we'll also need the formula for a SSS triangle

Cos(C) = a^2 + b^2 - c^2 / 2ab

keeping the above in mind we can now solve both triangles

c = AC for the first triangle

solve law of cosines for what we know

c^2= 17^2 + 30^2 - 2*17*30*Cos(100)

c = 36.96

now use SSS triangle formula to find the angle C, but c = 17 now , not 36.96, that's b

C = arcCos(17^2+36.96^2-30^2/ 2*17*36.96)

C = 42.24°

now use 180 = 100 +42.24 +A to solve the last angle

A= 37.75°

Triangle 1 solved

A= 37.75°

B= 100

C = 42.24°

a= 17

b=30

c=36.96

Triangle 2

given a=17 , b= 18 , c =30

use SSS formula to find one angle, which ever one you want in this case

Cos(C) = a^2 + b^2 - c^2 / 2ab

C = arcCos(17^2+18^2-30^2 / 2*17*18

C= 117.966°

solve for A now

Cos(A) =b^2+c^2-a^2 / 2bc

A = arcCos(18^2+30^2-17^2/2*18*30)

A = 30.03

use 180 again to solve for last angle

180 = 117.966+30.03+B

32.001 = B

Triangle 2 solved

A = 30.03°

B= 32.001°

C= 117.966°

a=17

b=18

c=30

:P whew

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Triangle ABC has vertices A(-3,0) B(0,6) C(4,6). Find the equations of the three medians of triangle ABC

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1. $y=-6x+6, y=\frac{6}{5} x+\frac{18}{5}, y=\frac{6}{11} x+\frac{42}{11}$

2. $y=-\frac{1}{2} x+2\frac{1}{4} , x=2, y=-\frac{7}{6}x+\frac{43}{12}$

Step-by-step explanation:

A(−3, 0), B(0, 6), and C(4, 6)

using the midpoint formula: $(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$ we can find all of their midpoint which is necessary to complete question 1 and 2

Mid AB=(-1.5, 3), Mid BC=(2, 6), Mid AC=(0.5,3)

Next, we have to find the slope of from the vertex and the midpoint of each side. We use the slope formula: $\frac{y_2-y_1}{x_2-x_1}$ .

You would get -6, 6/5, and 6/11.

Next you substitute in the coordinates for the equation of each for example: y=-6x, you switch in the set of cords AB which is (-1.5, 3). 3=-6(-1.5)+z and find that z=6, so the equation is y=-6x+6. As for the rest, repeat the same process until you find all 3 cords. You should get an answer of $y=-6x+6, y=\frac{6}{5} x+\frac{18}{5}, y=\frac{6}{11} x+\frac{42}{11}$

For question 2,

The line has to be perpendicular bisector to the midpoint, signifying that it has to split 2 angles into congruent angles and a side into half. In order to do that we need to first find the opposite reciprocal of each side's slope. Which means we need to once again use the slope formula and get the opposite reciprocal by $-\frac{1}{slope}$ . For all the opposite reciprocal slopes you get will be incorporated into the final formulas. That gives us the slopes of -1/2, 0 and -7/6. Then do the same process of matching cords with these incomplete equations and you can find the final equations of $y=-\frac{1}{2} x+2\frac{1}{4} , x=2, y=-\frac{7}{6}x+\frac{43}{12}$