ANSWER :
Surface area of larger cone : 24π units^2
Surface area of smaller cone : 6π units^2
The surface area of the smaller cone is 25% of that of the larger cone.
EXPLANATION :
From the given problem,
AB = 3 is the radius of the larger cone and the slanted height is BC = 5
DE = 1.5 is the radius of the smaller cone and the slanted height is EC = 2.5
Recall the surface area of the cone :
![A=\pi r^2+\pi rL](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%2B%5Cpi%20rL)
where r = radius and L = slanted height.
For the larger cone, r = 3 and L = 5
![\begin{gathered} A=\pi(3)^2+\pi(3)(5) \\ A=24\pi \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%5Cpi%283%29%5E2%2B%5Cpi%283%29%285%29%20%5C%5C%20A%3D24%5Cpi%20%5Cend%7Bgathered%7D)
For the smaller cone, r = 1.5 and L = 2.5
![\begin{gathered} A=\pi(1.5)^2+\pi(1.5)(2.5) \\ A=6\pi \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%5Cpi%281.5%29%5E2%2B%5Cpi%281.5%29%282.5%29%20%5C%5C%20A%3D6%5Cpi%20%5Cend%7Bgathered%7D)
Comparing the surface areas :
The area of the smaller cone compared to the larger cone is :
Answer:
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Step-by-step explanation:
i should try quizlet it helps me alot
The fromula of a slope:
![m=\dfrac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
a) (-1, -8), (-7, -4)
substitute
![m=\dfrac{-4-(-8)}{-7-(-1)}=\dfrac{-4+8}{-7+1}=\dfrac{4}{-6}=-\dfrac{2}{3}](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B-4-%28-8%29%7D%7B-7-%28-1%29%7D%3D%5Cdfrac%7B-4%2B8%7D%7B-7%2B1%7D%3D%5Cdfrac%7B4%7D%7B-6%7D%3D-%5Cdfrac%7B2%7D%7B3%7D)
b) (2.1, 3.8), (3.1, 7.6)
substitute
![m=\dfrac{7.6-3.8}{3.1-2.1}=\dfrac{3.8}{1}=3.8](https://tex.z-dn.net/?f=m%3D%5Cdfrac%7B7.6-3.8%7D%7B3.1-2.1%7D%3D%5Cdfrac%7B3.8%7D%7B1%7D%3D3.8)
Answer:
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Answer:
2128.5
Step-by-step explanation:
maybe this is the answer, i used calculator