Answer:
(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
Step-by-step explanation:
Let's denote the events as follows:
<em>A</em> = Fell short of expectations
<em>B</em> = Met expectations
<em>C</em> = Surpassed expectations
<em>N</em> = no response
<u>Given:</u>
P (N) = 0.04
P (A) = 0.26
P (B) = 0.65
(a)
Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:
Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b)
The response of all individuals are independent.
Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:
Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
Answer: She will use 6 cans of pinto beans .
She will use 6 cans of kidney beans.
Step-by-step explanation:
As per given,
For bean salad : lima beans : pinto beans : kidney beans
= 3:2:2
Let quantity of lima beans = 3x, pinto beans 2x , kidney beans 2x.
if she use 9 cans of lima beans, then
3x=9
⇒x=9
Now, 2x= 2 x 3 =6
Thus , she will use 6 cans of pinto beans and 6 cans of kidney beans.
10x10=100
4.1x100=410
So, the answer is 410.