X^2-12x+7=0 move constant to other side
x^2-12x=-7 add the square of half the linear coefficient to both sides...(12/2)^2=36
x^2-12x+36=29 now the left side is a perfect square...
(x-6)^2=29 so if
f(x)=(x-a)^2+b then
f(x)=(x-6)^2-29
So a=6
2 acute angles
just make a right angle and close it
Where is it I can’t see anything
6/319 = 0.0188087774
I used a calculator
or, just use long division
Have a great day!
Stay safe and healthy!
Happy holiday seasons!
May I please have brainliest?
