We know that the probability of a certain hockey player making a goal after hitting a slap shot is 
.
We need to figure out the number of successful slap shots if she makes 120 attempts?
Since the player is able to make a goal once out of 5 attempts. Therefore, in order to find the number of goals that we can expect the player to make successfully if she attempts 120 slap shots we will multiply the probability with 120.
Number of successful goals = (Probability of making one goal)x(Number of attempts)
Number of successful goals = 
.
Therefore, player will be able to make 24 goals out of 120 attempts.
Answer:
See below
Step-by-step explanation:
we have f(x) = -(x-7) + 3
and we want to find f(4)
essentially, f(4) means that the input is 4 and to find the output we plug in the value of the input where ever x is and evaluate.
So for f(x) = -(x-7) + 3
To find f(4) we replace all x's with 4
f(4) = -(4-7) + 3
we now evaluate
==> subtract 7 from 4
f(4) = -(-3) + 3
==> apply two negative rule ( basically if there are two negative signs they cancel out and the number turn positive )
f(4) = 3 + 3
==> add 3 and 3
f(4) = 6
Answer:
C) S = {F, PF, PPF, PPP}
Step-by-step explanation:
For this case, we know that a person is trying to gain access to a bank vault and needs to go through 3 security doors, and we know that if the person does not pass a door, then he/she has no other attempts. We denote P= Successful pass , F= Failed pass
And we are interested on the sample space, we need to remember that the sample is the set with all the possible values for an experiment.
For this case the person can fail at the 1,2 or 3 try
For the case that fails at the 1 try we have F
For the case that fails at the 2 try we have PF
For the case that fails at the 3 try we have PPF
And the last option is that the person not fails at any try and we have PPP
So then the sample space would be given by:
C) S = {F, PF, PPF, PPP}
The
<u>correct diagram</u> is attached.
Explanation:
Using technology (such as Geogebra), first construct a line segment. Name the endpoints C and D.
Construct the perpendicular bisector of this segment. Label the intersection point with CD as B, and create another point A above it.
Measure the distance from C to B and from B to D. They will be the same.
Measure the distance from A to B. If it is not the same as that from C to B, slide A along line AB until the distance is the same.
Using a compass and straightedge:
First construct segment CD, being sure to label the endpoints.
Set your compass a little more than halfway from C to D. With your compass set on C, draw an arc above segment CD.
With your compass set on D (the same distance as before) draw an arc above segment CD to intersect your first arc. Mark this intersection point as E.
Connect E to CD using a straightedge; mark the intersection point as B.
Set your compass the distance from C to B. With your compass on B, mark an arc on EB. Mark this intersection point as A.
AB will be the same distance as CB and BD.
Answer:
well that is a pretty good deal i might have to go there
Step-by-step explanation:
