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3 years ago

Please help ASAP! Answer the questions like 1. 2. 3 pls

Mathematics

2 answers:

Snezhnost [94]3 years ago

8 0

Answer:

1. 3, because 30 divided by 10 is 3.

2-6, What is the recipe? By understanding the OG recipe I can multiply every number by three.

You can put the recipe in the comments and I will edit this answer. :)

~PumpkinSpice1

attashe74 [19]3 years ago

7 0

3 is your lucky number

For question one, You need to multiply 10 by 3. To get this you can divide 30 by 10, this gives you the number you need to multiply 10 by, in this case its 3.

The next two questions are not able to be answered because I need the amount of oil or flour to determine how much to use for 30 cupcakes.

But, if you have 1 cup of oil for 10 servings, and you want 30 servings, like before, multiply by 3.

Same for flour, it doesnt matter how much of it you need, just multiply by 3 from the amount you use for 10 servings.

If your confused on 4, 5 and 6. Just remember, 3 is the lucky number.

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Help please I’ll make it brainliest!!!!!

mr Goodwill [35]

Step-by-step explanation:

it is very simple, once you remember that "kilo" means 1000, "mili" means 1/1000, and "centi" means 1/100.

and therefore 1 cg = 10 mg, or 1 cm = 10 mm.

"deci" means 1/10.

and therefore 1 dm = 100 mm, 1dg = 100 mg.

9.32 kg = 9.32×1000 = 9320 g

1.429 g = 1.429/1000 = 0.001429 kg

287 g = 287/1000 = 0.287 kg

4.6 L = 4.6×1000 = 4600 mL

0.119 L = 0.119×1000 = 119 mL

9936 mL = 9936/1000 = 9.936 L

26793 mL = 26793/1000 = 26.793 L

0.06 L = 0.06×1000 = 60 mL

170 cg = 170×10 = 1700 mg

10.

2674 cm = 2674/100 = 26.74 m

11.

9.05 mm = 9.05/100 = 0.0905 dm

12.

2 L = 2×1000 = 2000 mL

13.

62.4 L = 62.4×1000 = 62400 mL

14.

99.9 mm = 99.9/1000 = 0.0999 m

15.

4.34 g = 4.34×100 = 434 cg

16.

10 km = 10×1000 m = 10×1000×1000 = 10000000 mm

17.

65 cL = 65/100 = 0.65 L

18.

105 mL = 105/1000 = 0.105 L

19.

0.27 g = 0.27×100 = 27 cg

20.

7777 m = 7777/1000 = 7.777 km

4 0

2 years ago

Which number logically follows this series 4 6 9 6 14 6?

Firlakuza [10]

I would say 19.
If you take out the 6s and just look at the rest you have 4, 9, 14.
It is adding 5 each time and just have a 6 between each one.
So logically I would say 19.

3 0

3 years ago

Simplify u^2+3u/u^2-9<br> A.u/u-3, =/ -3, and u=/3<br> B. u/u-3, u=/-3

VashaNatasha [74]

  The correct answer is: Answer choice: [A]:
__________________________________________________________
→  " $\frac{u}{u-3}$ " ; " { u $\neq$ ± 3 } " ;

  →  or, write as: " u / (u − 3) " ;  {" u ≠ 3 "}  AND: {" u ≠ -3 "} ;
__________________________________________________________
Explanation:
__________________________________________________________
We are asked to simplify:

   $\frac{(u^2+3u)}{(u^2-9)}$ ;

Note that the "numerator" —which is: "(u² + 3u)" — can be factored into:
  → " u(u + 3) " ;

And that the "denominator" —which is: "(u² − 9)" — can be factored into:
  → "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→ $\frac{u(u+3)}{(u-3)(u+3)}$ ;

___________________________________________________________

→ We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" $\frac{(u+3)}{(u+3)} = 1$ " ;

→ And we have:
_________________________________________________________

→  " $\frac{u}{u-3}$ " ; that is: " u / (u − 3) " ; { u $\neq 3$ } .
and: { u $\neq-3$ } .

→ which is:  "Answer choice: [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ;

and if the denominator is "(u − 3)" ; the denominator equals "0" when "u = -3" ; as such:

"u $\neq$ 3" ;

→ Note: To solve: "u + 3 = 0" ;

Subtract "3" from each side of the equation;

→ " u + 3 − 3 = 0 − 3 " ;

→ u = -3 (when the "denominator" equals "0") ;

→ As such: " u $\neq$ -3 " ;

Furthermore, consider the initial (unsimplified) given expression:

→   $\frac{(u^2+3u)}{(u^2-9)}$ ;

Note:  The denominator is: "(u²  − 9)" .

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ;

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________

→ " u² − 9 = 0 " ;

→ Add "9" to each side of the equation ;

→ u² − 9 + 9 = 0 + 9 ;

→ u² = 9 ;

Take the square root of each side of the equation;
to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ;

→ √(u²) = √9 ;

→ | u | = 3 ;

→ " u = 3" ; AND; "u = -3 " ;

We already have: "u = -3" (a value at which the "denominator equals "0") ;

We now have "u = 3" ; as a value at which the "denominator equals "0");

→ As such: " u $\neq 3$ " ; "u $\neq$ -3 " ;

or, write as: " { u $\neq$ ± 3 } " .

_________________________________________________________

6 0

3 years ago

The answer I don’t know how to do this promem

cupoosta [38]

Answer: if you show us the whole picture, maybe we will be able to solve it?

Step-by-step explanation:

just retake the picture so i can see the whole thing

8 0

3 years ago

Help with this problem

erastova [34]

60% is your answer. Good luck!!

7 0

3 years ago