G(n) = n + 3 f(n) = n + 1 Find (g•f)(-4)

HURRY PLEASE SHOW UR WORK AND WILL GIVE BRAINLIEST !!!

EastWind [94]

Answer:

im not exactly sure, but i think it would be PART A: either option B or D by going diagonal across the grid and then normal across the grid. PART B: option B because that is the shortest option going diagonal that matches with the options available

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Consider the sequence of steps to solve the equation: 3(x − 4) + 5x = 9x − 36 Given ⇒ 3(x − 4) + 5x = 9x − 36 Step 1 ⇒ 3x − 12 +

7nadin3 [17]

In Step 6, the equation is ...

-12 = x - 36

In step 7, the equation is ...

-12 +36 = x -36 +36

Clearly, to get to step 7, 36 has been added to both sides of the equation.

Adding 36 to both sides of the equation is justified by ...

... C) Addition Property of Equality

_____

More about the addition property of equality

The addition property of equality says you can add the same value to both sides of an equation without changing the values of the variables that make the equation true. Here, x=24 makes the equation of step 6 true, and x=24 makes the equation of step 7 true.

7 0

3 years ago

Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$

Substitute:

$\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}$

Combine fractions:

$\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}$

Simplify:

$\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}$

Simplify:

$6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}$

Q.E.D.

6 0

3 years ago

A pair of pants regularly costs $68. The pants are on sale for 45% of the original price. How much will the discount be?

Novay_Z [31]

The discounted amount of pair of pants is $37.4

Solution:

Given, A pair of pants regularly costs $68.

The pants are on sale for 45% of the original price.

We have to find that how much will the discount be?

Now, discounted amount = original price – sold price

Discounted amount = original price – 45% of original price

Discounted amount = $68 – 45% of $68

$\begin{array}{l}{=68-\frac{45}{100} \times 68=68\left(1-\frac{45}{100}\right)=68 \times \frac{100-45}{100}=68 \times \frac{55}{100}} \\\\ {=\frac{3740}{100}=\$ 37.4}\end{array}$

Hence, the discounted amount is $37.4

6 0

3 years ago

Point O is the center of this circle. What is m CAB? A.55 B.48 C.45 D.35

Sophie [7]

Answer is B. 48

By circle theorem, the angle at the centre of the circle is twice the angle at the circumference.

3 0

2 years ago