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Amanda [17]
3 years ago
6

Anyone know how to fix black screen of death on computer​

Computers and Technology
1 answer:
jonny [76]3 years ago
7 0

Answer:

you asked a question so you must have fixed it

Explanation:

logic

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Which of the following statements is/are correct? a. At the network layer, entitlement can map identity and/or attributes to fun
AlekseyPX

Answer:

Option D

Explanation:

An Entitlement is an option to utilize, get to or devour an application or asset, commonly for a charge. For instance, a client may buy an Entitlement to utilize an application in ceaselessness (a "unending" permit), or they may buy a period restricted option to utilize an application, (for example, a one-year membership permit).

7 0
3 years ago
Both the USB flash drive and the DVD are data storage devices, but they both have numerous differences. Both can contain insane
o-na [289]
It Is Wonderful Add That A "USB" Can Hold Anything At All But Some Thing's "System's" Need A Specific Format Like The "PlayStation Three" With "FAT32" Format.
6 0
4 years ago
A group consists of 10 kids and 2 adults. On a hike, they must form a line with an adult at the front and an adult at the back.
blsea [12.9K]

Answer:

b. 2.9!

Explanation:

There are is a mistake in the question.

Suppose the group consist of 10 kids and 2 adults, the number of ways in which they can form the line is:

= 2! 10!

= 2× 1× 10!

= 2.10!

But since that is not in the given option.

Let assume that the group consists of 9 kids and 2 adults, the number of ways in which they can form the line is:

No of ways the kids can be permutated =  9 ways

No of ways the adult can be permutated  = two ways.

Thus; the number of ways in which they can form the line = 2! 9!

= 2 × 1× 9!

= 2.9!

6 0
3 years ago
A palindrome is a string that reads the same from left to right and from right to left. Design an algorithm to find the minimum
stepladder [879]

Answer:

Explanation:

The following code is written in Python. It is a recursive function that tests the first and last character of the word and keeps checking to see if each change would create the palindrome. Finally, printing out the minimum number needed to create the palindrome.

import sys

def numOfSwitches(word, start, end):

   if (start > end):

       return sys.maxsize

   if (start == end):

       return 0

   if (start == end - 1):

       if (word[start] == word[end]):

           return 0

       else:

           return 1

   if (word[start] == word[end]):

       return numOfSwitches(word, start + 1, end - 1)

   else:

       return (min(numOfSwitches(word, start, end - 1),

                   numOfSwitches(word, start + 1, end)) + 1)

word = input("Enter a Word: ")

start = 0

end = len(word)-1

print("Number of switches required for palindrome: " + str(numOfSwitches(word, start, end)))

3 0
3 years ago
Create a Card class that represents a playing card. It should have an int instance variable named rank and a char variable named
Helen [10]

Answer:

Explanation:

The following code is written in Java. It creates the Card class and then uses it to create a full house and print out the rank and suit of every card in that hand.

class Card {

   int rank;

   char suit;

   public Card(int rank, char suit) {

       this.rank = rank;

       this.suit = suit;

   }

   public int getRank() {

       return rank;

   }

   public char getSuit() {

       return suit;

   }

}

class CardTester {

   public static void main(String[] args) {

       Card card1 = new Card(3, '♥');

       Card card2 = new Card(3, '♠');

       Card card3 = new Card(3, '♦');

       Card card4 = new Card(2, '♦');

       Card card5 = new Card(2, '♣');

       System.out.println("Card 1: " + card1.getRank() + " of " + card1.getSuit());

       System.out.println("Card 2: " + card2.getRank() + " of " + card2.getSuit());

       System.out.println("Card 3: " + card3.getRank() + " of " + card3.getSuit());

       System.out.println("Card 4: " + card4.getRank() + " of " + card4.getSuit());

       System.out.println("Card 5: " + card5.getRank() + " of " + card5.getSuit());

   }

}

3 0
3 years ago
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