Find the rule ans the graph of the function whose graph can be obtained by performing the translation 4 units peft and 5 units d
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<h3>Option B</h3><h3>At 2 second and 1.75 second, the object be at a height of 56 feet</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation:</u></em>
<em><u>At what times will the object be at a height of 56 feet</u></em>
<em><u>Substitute h = 56</u></em>
Solve the above equation by quadratic formula
Thus, at 2 second and 1.75 second, the object be at a height of 56 feet
First, convert that into a y=mx+b form.
Move the x to the other side so y is the only thing on the left. Since you moved it to the other side of the equal sign, be sure to make that number negative (the opposite sign)
Now… you have 4y=-3x+28
Let’s get y by itself. Since you’re multiplying 4 and y, you divide everything by 4 to get your y.
That leaves you with y=-3/4x+7.
We are looking at slope, which is your m in the y=mx+b form.
That is -3/4. The answer is the last square.
Move the x to the other side so y is the only thing on the left. Since you moved it to the other side of the equal sign, be sure to make that number negative (the opposite sign)
Now… you have 4y=-3x+28
Let’s get y by itself. Since you’re multiplying 4 and y, you divide everything by 4 to get your y.
That leaves you with y=-3/4x+7.
We are looking at slope, which is your m in the y=mx+b form.
That is -3/4. The answer is the last square.