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shepuryov [24]
3 years ago
13

Rewrite this if/else if code segment into a switch statement int num = 0; int a = 10, b = 20, c = 20, d = 30, x = 40; if (num &g

t; 101 && num <= 105) { a += 1; } else if (num == 208) { b += 1; x = 8; } else if (num > 208 && num < 210) { c = c * 3; } else { d += 1004; }
Computers and Technology
1 answer:
Tanya [424]3 years ago
3 0

Answer:

public class SwitchCase {

   public static void main(String[] args) {

       int num = 0;

       int a = 10, b = 20, c = 20, d = 30, x = 40;

       switch (num){

           case 102: a += 1;

           case 103: a += 1;

           case 104: a += 1;

           case 105: a += 1;

           break;

           case 208: b += 1; x = 8;

           break;

           case 209: c = c * 3;

           case 210: c = c * 3;

           break;

           default: d += 1004;

       }

   }

}

Explanation:

  • Given above is the equivalent code using Switch case in Java
  • The switch case test multiple levels of conditions and can easily replace the uses of several if....elseif.....else statements.
  • When using a switch, each condition is treated as a separate case followed by a full colon and the the statement to execute if the case is true.
  • The default statement handles the final else when all the other coditions are false
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Write a program that takes an integer n as a parameter and sums all of the multiples of 2 or 5 from 1 to n. For example, if n =
Alex

Answer:

// here is code in c++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

// variable

int num;

int tot_sum=0;

cout<<"enter a number: ";

// read the value of n

cin>>num;

// check the multiple of 2 or 5 from 1 to n

for(int x=1;x<=num;x++)

{

// if multiple of 2 or 5 then add them

   if(x%2==0 ||x%5==0)

   {

       tot_sum=tot_sum+x;

   }

}

// print the sum

cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;

return 0;

}

Explanation:

Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.

Output:

enter a number:11

sum of multiple of 2 or 5 is:35

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Answer:

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