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blsea [12.9K]
3 years ago
7

Sliced Cheese

Mathematics
1 answer:
mart [117]3 years ago
8 0
Hope this vhn ty nooo
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What is /-3/*-6?<br><br> When you answer could you please explain to me why the answer is that?
jekas [21]
|-3|=3 right?
Then it is
3*-6=-18
8 0
3 years ago
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So \mu = 375, \sigma = 68

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So n = 6, s = \frac{68}{\sqrt{6}} = 27.76

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 375}{27.76}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So \mu = 522, \sigma = 106

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So n = 6, s = \frac{106}{\sqrt{6}} = 43.27

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 523}{43.27}

Z = -2.61

Z = -2.61 has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0
3 years ago
I need help asap someone please help ​
Dvinal [7]

Answer:

c = 20

so , c >20 ...........

8 0
2 years ago
Easy math problem plz Halp
yan [13]
The answer is 19.5

You add all the numbers to get 273 and divide by the amount of dots which is 14 to get 19.5
6 0
2 years ago
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Sam Long anticipates he will need approximately $227,300 in 14 years to cover his 3-year-old daughter's college bills for a 4-ye
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Answer:

which of these expressions or phrases can be used to represent the model brainly choose al the correct answerswhich of these expressions or phrases can be used to represent the model brainly choose al the correct answerswhich of these expressions or phrases can be used to represent the model brainly choose al the correct answerswhich of these expressions or phrases can be used to represent the model brainly choose al the correct answerswhich of these expressions or phrases can be used to represent the model brainly choose al the correct answerswhich of these expressions or phrases can be used to represent the model brainly choose al the correct answerswhich of these expressions or phrases can be used to represent the model brainly choose al the correct answerswhich of these expressions or phrases can be used to represent the model brainly choose al the correct answerswhich of these expressions or phrases can be used to represent the model brainly choose al the correct answers

Step-by-step explanation:

4 0
3 years ago
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