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nika2105 [10]
3 years ago
6

The radius of a circle is 4.53 inches what is the length of the circumference of the circle ?

Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0

Answer:

28.46in

Step-by-step explanation:

C=2πr

C=2π*4.53

C≈28.46in

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A map of Rockbridge County has a scale factor of
malfutka [58]

Answer: 6 inch

Step-by-step explanation:

From the question, we are informed that a map of Rockbridge County has a scale factor of 2.5 in = 5 miles.

When the actual distance from Fairfield to Lexington is 12 miles, the distance on the map will be:

= 12/5 × 2.5

= 2.4 × 2.5

= 6 inch

6 0
3 years ago
In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any
Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

E \cap F = \emptyset,\quad E \cup F = \Omega

where \Omega is the whole sample space.

This implies that

P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day d_1.

The second footballer can be born on any other day, so he has 364 possible birthdays:

d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}

the probability for the first two footballers to be born on two different days is thus

1 \cdot \dfrac{364}{365} = \dfrac{364}{365}

Similarly, the third footballer can be born on any day, except d_1 and d_2:

d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}

so, the probability for the first three footballers to be born on three different days is

1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

So, the probability that at least two footballers are born on the same day is

1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}

since the two events are complementary.

8 0
3 years ago
PLEASE HELP ME I WILL GIVE BRAINLIEST
Leokris [45]

Answer:

there are fourteen 4-point questions and twenty six 2-point questions.

Step-by-step explanation:

Given : A 40-question test has 108 possible points.

There are m 4-point questions and n 2-point questions.

So , equation for total number of questions in the test :

m + n = 40 | 4n + 2n = 108

Multiplying (i) by 2 , we get

2m + 2n = 80

Subtract (iii) from (ii) , we get

2m = 28

⇒ m = 28/ 2 = 14

Using value of m in (i) , we get

14 + n = 40 ⇒ n = 26

from this we get there are fourteen  4-point questions and twenty six 2-point questions.

hope this helped!

3 0
3 years ago
Can someone help me solve this problem? ill give brainliest to the one who answers the fastest and is most correct!
adelina 88 [10]

Answer:

They both equal zero

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
Find other coordinate for the line 3x-5y=2 (2,_)
lisabon 2012 [21]
The coordinate is (2, y). Substitute x=2:

3 * 2 - 5y = 2 

6-5y = 2

-5y=-4    |:(-5)

y=0.8

The coordinate is (2, 0.8)
4 0
3 years ago
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