Answer:
8...the value of d variable =45 degree
corresponding angles are equal(reason)
9.
Answer:
one solution
Step-by-step explanation:
3(x-2) =22 -x
Distribute
3x - 6 = 22-x
Add x to each side
3x+x-6 = 22-x+x
4x+6 = 22
Subtract 6 from each side
4x+6-6 = 22-6
4x= 16
Divide by 4
4x/4 = 16/4
x=4
There is one solution
Answer:
y = -2.8x +69.4
Step-by-step explanation:
Let y represent units of inventory, and x represent days since the last replenishment. We are given points (x, y) = (3, 61) and (13, 33). The line through these points can be described using the 2-point form of the equation of a line:
... y -y1 = (y2-y1)/(x2 -x1)(x -x1)
Filling in the given point values, we have ...
... y -61 = (33 -61)/(13 -3)(x -3)
Simplifying and adding 61, we get ...
... y = -2.8x +69.4
Step One
Find the fraction left.
Starting amount = 7/8 pound
Used amount = 1/7 of a pound.
The common denominator of these two fractions is 8 * 7 = 56
Amount left = amount started with - amount used
Amount left = 7/8 - 1/7
Amount left =

Amount left =

Amount left = 41 / 56 pounds
Step Two
Convert the Answer to ounces.
Ounces = (41/56) * 16
Ounces = 11.71 ounces almost 11 3/4
Answer:
89–100
Step-by-step explanation:
Let x represent the grade on the fifth test. The average for 5 tests wants to be between 80 and 90, so we have ...
80 ≤ (78 +62 +91 +80 +x)/5 ≤ 90
Multiplying by 5 gives
400 ≤ 311 +x ≤ 450
Subtracting 311 gives the range for the fifth test grade.
89 ≤ x ≤ 139
Since the maximum available score is 100, the range on the 5th test for an overall B grade is ...
89 ≤ x ≤ 100 . . . . where x is the grade on the 5th test