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3 years ago

(16+5i) + (6-7i)How do I solve this?

Mathematics

2 answers:

Slav-nsk [51]3 years ago

6 0

Answer:

22-2i

Explanation:

16+6=22

5i-7i=-2i

Fantom [35]3 years ago

5 0

Answer:

$\large\boxed{(16+5i)+(6-7i)=22-2i}$

Step-by-step explanation:

$(16+5i)+(6-7i)=16+5i+6+7i\qquad\text{combine like terms}\\\\=(16+6)+(5i-7i)=22-2i$

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Which of the following equations have complex roots?

brilliants [131]

Answer:

Step-by-step explanation:

5 0

3 years ago

A pound of blueberries costs $3.98 and a pound of clementines costs $2.49. What is the combined cost of 0.6 pound of blueberries

siniylev [52]

The combined cost of 0.6 pound of blueberries and 1.8 pounds of clementines is $ 6.87

Solution:

Given that,

Cost of 1 pound of blueberries = $ 3.98

Cost of 1 pound of clementines = $ 2.49

To find: combined cost of 0.6 pound of blueberries and 1.8 pounds of clementines

Let us first find cost of 0.6 pound of blueberries

cost of 0.6 pound of blueberries = 0.6 x Cost of 1 pound of blueberries

$\rightarrow 0.6 \times 3.98 = 2.388$

Thus, cost of 0.6 pound of blueberries is $ 2.388

Find cost of 1.8 pounds of clementines

cost of 1.8 pound of clementines = 1.8 x cost of 1 pound of clementines

$\rightarrow 1.8 \times 2.49 = 4.482$

Thus, cost of 1.8 pound of clementines is $ 4.482

Find combined cost of 0.6 pound of blueberries and 1.8 pounds of clementines

Combined cost = cost of 0.6 pound of blueberries + cost of 1.8 pound of clementines

Combined cost = 2.388 + 4.482 = 6.87

Thus combined cost of 0.6 pound of blueberries and 1.8 pounds of clementines is $ 6.87

5 0

3 years ago

Write the equation for a line that passes through the points (5,5) and (7,-5)

julia-pushkina [17]

This equation would be equal to y = -5x + 30

3 0

3 years ago

Read 2 more answers

Two random variables x and y are independent if the value of x does not affect the value of y. If the variables are not indepen

jeyben [28]

Answer: $\mu_{x+y} =$ 3026

$\mu_{x-y}=$ 30

Step-by-step explanation: Average sum of the female and male's test score is the sum of expected value of each gender:

$\mu_{x+y}=\mu_{x}+\mu_{y}$

Assuming x represents the random male selected and y represents the random female selected:

$\mu_{x+y}=1528+1498$

$\mu_{x+y}=$ 3026

The average sum of their scores is 3026.

Average difference is the difference between the expected value (mean) of each gender:

$\mu_{x-y}=\mu_{x}-\mu_{y}$

$\mu_{x-y}=$ 1528 - 1498

$\mu_{x-y}=$ 30

The average difference of their scores is 30.

6 0

3 years ago

P is a rectangle with a length 40 cm and width x cm

Vesnalui [34]

We know that
the length of Q is 25% more than the length of p
so
length Q=1.25*40--------> 50 cm

the area of Q is 10% less than the area of p
Area Q=50*y
Area P=40*x
so
50*y=0.90*[40*x]---------> 50*y=36*x-------> x/y=50/36---> 25/18

the answer is
the ratio x:y is
25:18

7 0

3 years ago

(16+5i) + (6-7i)How do I solve this?​

(16+5i) + (6-7i)How do I solve this?