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notka56 [123]
2 years ago
9

¿Cual es el error maximo que se puede cometer al medir el diametro de un circulo, cuya medida es 10 cm y la tolerancia debe ser

de 5%?
Mathematics
1 answer:
ZanzabumX [31]2 years ago
3 0

Usando proporciones, hay que el error maximo que se puede cometer al medir el diametro de un circulo, en cm, es de \pm 0.5.

<h3>¿Qué es una proporción?</h3>

Una proporción es una fracción de la cantidad total.

En este problema:

  • La cantidad total es el diametro de un circulo, cuya medida es 10 cm.
  • El erro maximo es de 5% de esto, o sea:

\pm 0.05(10) = 0.5

El error maximo que se puede cometer al medir el diametro de un circulo, en cm, es de \pm 0.5.

Puede-se aprender más a cerca de proporciones en brainly.com/question/26395519

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The table displays the frequency of scores for a calculus class on an exam. The mean of the exam scores is 3.5. Score 1 2 3 4 5
vladimir1956 [14]

Answer:

f=11

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Explanation:

We are given that

a.Mean of the exam score,\bar x=3.5

Score(x)   frequency   C.F

1                  1                 1

2                  3                4

3                  f                 15(4+f=4+11)

4                  13               28

5                   4               32

\sum f_i=1+3+f+13+4=21+f

\sum f_ix_i=1(1)+2(3)+3(f)+4(13)+5(4)=1+6+3f+52+20=79+3f

(\bar x)=\frac{\sum f_ix_i}{\sum f_i}

Using the formula

3.5=\frac{79+3f}{21+f}

73.5+3.5f=79+3f

3.5f-3f=79-73.5

0.5f=5.5

f=\frac{5.5}{0.5}=11

b.Mode:The number which is repeat most times .

4 repeat most times

Hence, mode of all exam scores=4

N=32

N is even

Median=\frac{(\frac{n}{2})^{th}+(\frac{n}{2}+1)^{th}}{2}

Median=\frac{16th+17th}{2}=\frac{4+4}{2}=\frac{8}{2}=4

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Answer:

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Step-by-step explanation:

The rate of change in revenue  dR/dt for Priceline Group is

dR/dt =  0,07*e∧0,2387*t

dR = (0,07*e∧0,2387*t ) * dt

∫dR = ∫ (0,07*e∧0,2387*t ) * dt       between 2004  to 2013   ( t = 4 stands for 2004 and t = 13 stands for 2013 )

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R(12)  = 0,7602 +  5,1440

R(12)  =  5,9042 billions of dollars

8 0
3 years ago
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