Lewis Structure of
Oxygen Difluoride is sketched as....
Step 1: Calculate the
total number of valence electrons present in OF₂. This is done by adding all valence electrons of each element. i.e...
Valence e⁻s of Oxygen = 6
Valence e⁻s of Fluorine-1 = 7
Valence e⁻s of Fluorine-2 = 7
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Total Valence e⁻s
20Step 2: Draw central element (O) in center surrounded by fluorine atoms. Now, sketch a single bonds between O and both F atoms. Now, subtract 2 electrons per single bond from total valence electrons.. i.e..
Total Valence e⁻s = 20
2 single bonds (2 × 2) = 4
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16Now, distribute remaining 16 electrons on each element to complete its
octet starting from most electronegative element.
Lewis structure of OF₂ is as follow,
C, Electronegativity Increases
A molecule is the smallest unit of a chemical compound that still has the properties of that compound. Hope i helped :)
Answer:
https://download.cnet.com/1-Click-Answers/3000-2378_4-10060189.html
Explanation:
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