You have made use of the Le Chatelier principle in this lab. Explain how the Le Chatelierprinciple is used to help formation of
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The concentration of lead nitrate is 3.48 M.
<u>Explanation:</u>
The molarity can be found by dividing moles of sucrose by its volume in litres. We can find the number of moles of sucrose by dividing the given mass by its molar mass. Now we can find the moles as,
Here mass of Pb(NO₃)₂ is 380 g
Molar mass of Pb(NO₃)₂ is 331.2 g/mol
Number of moles =
=
= 1.15 moles
Volume in Litres = 330 ml = 0.33 L
Molarity =
= 3.48 mol/L or 3.48 M
So the concentration of lead nitrate is 3.48 M.
The percent yield of reaction = 65.27%
<h3>Further explanation</h3>Reaction
2Pb(s)+O₂(g)⟶2PbO(s)
mass of Lead(Pb) = 451.4 g
mol of Pb (MW=207 g/mol) :
mol of lead(II) oxide (PbO) based on mol Pb as a limiting reactant(Oxygen as an excess reactant) :
mass of PbO(MW=223 g/mol)⇒theoretical :
The percent yield :
theoretical = 486.14 g
actual = 317.3 g