Amount of CH4 is excess, so no need to worry about it
<span>but the limiting factor is the Oxygen </span>
<span>according to stranded equation, </span>
<span>CH4 + 2 O2 --> CO2 + 2 H2O ΔH = -889 kJ/mol </span>
<span>just by taking proportions </span>
<span>(-889 kJ/mol) / 2 x 0.8 mol = - 355.6 kJ </span>
<span>so i think the answer is (a)</span>
The given statement is True.
This is single replacement reaction.
As reactivity decreases down the group,
Iodine is less reactive than Chlorine.
And so Iodine cannot replace chlorine from FeCl2.
I2 + FeCl2 ---> no reaction (Iodine is less reactive than chlorine)
Answer:
Fe(CN)₂, FeCO₃, Pb(CN)₄, Pb(CO₃)₂
Explanation:
Cations (positively charged ions) can only form ionic bonds with anions (negatively charged ions). However, you can't just simply put one cation and one anion together to form a compound. Each compound needs to been neutral, or have an overall charge of 0. When cations and anions do not have charges that perfectly cancel, you need to modify the amount of each ion in the compound.
1.) Fe(CN)₂
-----> Fe²⁺ and CN⁻
-----> +2 + (-1) + (-1) = 0
2.) FeCO₃
-----> Fe²⁺ and CO₃²⁻
-----> +2 + (-2) = 0
3.) Pb(CN)₄
-----> Pb⁴⁺ and CN⁻
-----> +4 + (-1) + (-1) + (-1) + (-1) = 0
4.) Pb(CO₃)₂
-----> Pb⁴⁺ and CO₃²⁻
-----> +4 +(-2) + (-2) = 0
It would be MnSO4
The (II) lets you know it’s the form with a 2+ charge and Sulfate has a 2- charge
These will cancel out making it plain MnSO4
If it was manganese (iii) sulfide the answer would be Mn2(SO4)3
