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qwelly [4]
3 years ago
8

Which of the following increases the concentration of OH- ions?

Chemistry
2 answers:
ludmilkaskok [199]3 years ago
7 0

Answer:

Basee is the answer hope its write xd

Trava [24]3 years ago
3 0

Answer:

B: Base

Explanation:

An acid will increase the concentration of hydrogen (H+) ions in a solution, and a base would increase the concentration of hydroxide (OH–) ions in a solution. So, Base is the answer.  :)

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100 POINTS!!! AND BRAINLIEST!!!
Katen [24]

Answer:

it would have lots of greens and it would be darker cause all the tree would block the light

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Explanation:

4 0
3 years ago
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2C2H2(g) 5O2(g) → 4CO2(g) 2H2O(g) This is a balanced equation for the combustion of acetylene(C2H2). How many moles of oxygen(O2
omeli [17]

The moles of oxygen required to completely react with 1-mole acetylene is 2.5 mol.

The moles of reactant and product in a chemical reaction to the whole number ratio is given by the stoichiometric coefficient of the balanced chemical equation.

<h3>Computation for the moles of oxygen</h3>

The balanced chemical equation for the reaction is :

\rm 2\;C_2H_2\;+\;5\;O_2\;\to\;4\;CO_2\;+\;2\;H_2O

From the balanced chemical equation, the 2 moles of acetylene react with 5 moles of oxygen.

The moles of oxygen react with 1 mole of acetylene are:

\rm 2\;mol\;C_H_2=5\;mol\;O_2\\\\1\;mol\;C_2H_2=\dfrac{5}{2}\;\times\;1\;mol\;O_2\\\\ 1\;mol\;C_2H_2=2.5\;mol\;O_2

The moles of oxygen required to completely react with 1-mole acetylene is 2.5 mol.

Learn more about moles reacted, here:

brainly.com/question/24817060

8 0
3 years ago
Which of the following molecular compounds does NOT need the usage of prefix for the first element
Mrrafil [7]

Answer:

SO2

Explanation:

that's my answer

Sana mKatolong

3 0
2 years ago
The intensity of illumination at any point from a light source is proportional to the square of the reciprocal of the distance b
SSSSS [86.1K]

Answer:

the stronger light 5.5 m apart from the total illumination​

Explanation:

From the problem's statement , the following equation can be deducted:

I= k/r²

where I = intensity of illumination , r= distance between the point and the light source , k = constant of proportionality

denoting 1 as the stronger light and 2 as the weaker light

I₁= k/r₁²

I₂= k/r₂²

dividing both equations

I₂/I₁ = r₁²/r₂²=(r₁/r₂)²

solving for r₁

r₁ = r₂ * √(I₂/I₁)

since we are on the line between the two light​ sources , the distance from the light source to the weaker light is he distance from the light source to the stronger light + distance between the lights . Thus

r₂ = r₁ + d

then

r₁ = (r₁ + d)* √(I₂/I₁)

r₁ = r₁*√(I₂/I₁) + d*√(I₂/I₁)

r₁*(1-√(I₂/I₁)) =  d*√(I₂/I₁)

r₁ = d*√(I₂/I₁)/(1-√(I₂/I₁))  =

r₁ = d/[√(I₁/I₂)-1)]

since the stronger light is 9 times more intense than the weaker

I₁= 9*I₂ → I₁/I₂ = 9 →√(I₁/I₂)= 3

then since d=11 m

r₁ = d/[√(I₁/I₂)-1)] = 11 m / (3-1) = 5.5 m

r₁ = 5.5 m

therefore the stronger light 5.5 m apart from the total illumination​

5 0
3 years ago
Help me if not clear tell me
LenKa [72]

Answer:

make it clearer

Explanation:

.

3 0
3 years ago
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