A hypothetical element, E, has two stable isotopes. One isotope has a natural abundance of 68.037% and has an atomic mass of 46.
1 answer:
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Answer:
Reactivo límite: Superóxido de potasio.
Moles de oxígeno producidas:
Explanation:
Hola,
En este caso, considerando la reacción química llevada a cabo:
Es posible identificar el reactivo límite calculando las moles de superóxido de potasio que serían consumidas por 0.10 mol de agua por medio de la relación molar 4 a 2 que hay entre ellos:
Así, dado que solo hay 0.15 mol the superóxido de potasio, podemos decir que este es el reactivo límite. Luego, calculamos las moles de oxígeno producidas, considerando la relación molar 4 a 3 que hay entre el superóxido y el oxígeno:
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Answer: The given question is incomplete. The complete question is:
At a certain temperature the rate of this reaction is second order in with a rate constant of
.
Suppose a vessel contains at a concentration of 0.100 M Calculate how long it takes for the concentration of
to decrease to 0.0240 M. You may assume no other reaction is important. Round your answer to 2 significant digits.
Answer: It takes 0.93 seconds for the concentration to decrease to 0.0240 M.
Explanation:
Integrated rate law for second order kinetics is given by:
= initial concentration = 0.100 M
a= concentration left after time t = 0.0240 M
k = rate constant =
t = time taken for decomposition = ?
Thus it takes 0.93 seconds for the concentration to decrease to 0.0240 M.