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inessss [21]
2 years ago
14

HEY PLS HELP :))))))))))))

Mathematics
1 answer:
nevsk [136]2 years ago
3 0
What do you need help with I got you just send me itnjkjrhhvd
You might be interested in
What is the result when the number 64 is decreased by 4.1%? Round your answer to the nearest tenth.
Strike441 [17]

Answer:

61.4

Step-by-step explanation:

64 minus 4.1 percent is 61.376. Rounded to the nearest tenth would be 61.4.

3 0
2 years ago
Read 2 more answers
A biologist is studying rainbow trout that live in a certain river and she estimates their mean length to be 529 millimeters. As
vredina [299]

Answer:

See the book it will definitely help you

7 0
2 years ago
In a manufacturing process, a random sample of 36 bolts has a mean length of 3 inches with a standard deviation of .3 inches. Wh
Liula [17]

The 99 percent confidence interval for the true mean length of the bolt is CI = (2.8712, 3.1288)

<h3>How to find the confidence interval?</h3>

Confidence Interval is used to tell us the degree of certainty or uncertainty that is existent in a sampling method.

The general formula for confidence interval is;

CI = x' ± z(s/√n)

where;

x' is sample mean

z is z-score at confidence level

s is sample standard deviation

n is sample size

We are given;

sample size; n = 36

Sample mean; x' = 3 inches

standard deviation; s = 0.3 inches

confidence level = 99%

z at 99% CL = 2.576

Thus;

CI = 3 ± 2.576(0.3/√36)

CI = 3 ± 0.1288

CI = (2.8712, 3.1288)

Read more about Confidence Interval at; brainly.com/question/17097944

#SPJ1

3 0
1 year ago
Your high school is having a competition where students have to guess how many candy canes are in a jar. The tens digit is 4 mor
rodikova [14]

Answer:

40

Step-by-step explanation:

let ones be x

tens is 4 + 2x

4 + 2x + x = 4

3x = 0

x = 0

tens is 4 + 2*0

tens = 4

40 candy canes

5 0
2 years ago
Readings on a thermometer are normally distributed with a mean of 0C° and a standard deviation of 1.00. What is the probability
hichkok12 [17]

Given mean = 0 C and standard deviation = 1.00

To find probability that a random selected thermometer read less than 0.53, we need to find z-value corresponding to 0.53 first.

z= \frac{x-mean}{standard deviation}  = \frac{0.53-0}{1.00} = 0.53

So, P(x<0.53) = P(z<0.53) = 0.701944

Similarly P(x>-1.11)=P(z>-1.11) = 1-P(z<-1.11) = 0.8665

For finding probability for in between values, we have to subtract smaller one from larger one.

P(1.00<x<2.25) = P(1.00<z<2.25) = P(z<2.25)- P(z<1.00) = 0.9878 - 0.8413 = 0.1465

P(x>1.71) = P(z>1.71) = 1-P(z<1.71) = 1-0.9564 = 0.0436

P(x<-0.23 or x>0.23) = P(z<-0.23 or z>0.23)  =P(z<-0.23)+P(z>0.23) = 0.409+0.409 = 0.918

4 0
3 years ago
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