Part 1:
Fixed Cost, f = $20
number of balls = n
Cost of each ball, c = 4.32
Price of each ball, p = 8.32
Equation for total cost:
Total Cost of balls will come by adding the cost of all balls and the fixed cost
Total Cost = number of balls made × Cost of each ball + fixed cost
<em>C = 4.32n + 20</em>
Equation for revenue:
Revenue = Number of balls made × price of each ball
<em>R = 8.32n </em>
Part 2:
Use the graphing method to determine how many balls must be sold to break even
Breakeven means Revenue = total Cost
This happens at a point (5,41.6) where n = 5 is the number of balls sold
and C = 41.6 is the total cost
When 5 balls are sold there will be breakeven
R = 4n - 20
C = 4.32n + 20
Red line represent Cost
Black line represent Revenue
Answer:
4/9 or 44.44%
Step-by-step explanation:
We have the following probabilities:
Probability of winning the statistical test = P (s) = 2/3
Probability of winning the mathematics and statistics test = P (s n m) = 14/45
Probability of winning at least one test = P (s u m) = 4/5
We have that, the probability of winning the mathematics test P (m) can be found in the following way:
P (s n m) = P (s) + P (m) - P (s u m)
replacing we have:
14/45 = 2/3 + P (m) - 4/5
P (m) = 14/45 - 2/3 + 4/5
p (m) = 4/9 = 0.444
Which is the same as there is a 44.44% probability that I will win the math test
Answer:
a) x: 0,1,2,3,4,5,6,7,8
y: 0,8,16,24,32,48,56,64
b) label the horizontal line number of yards. The vertical line is costs, label each unit in 8s.
c) constant of porportionality is 8
d) y=8x
Answer:
16
Step-by-step explanation:
224/14=16
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or …show more content…
An observation of the Moon was conducted from Friday, November 8, 2013 to Thursday, November 14, 2013. The study of the Moon during this period occurred consistently between the hours of 8 and 9 p.m. EST within the Northern Hemisphere at 37.3346° N, 79.5228° W (Bedford, V.A.). The Moon was noted to be illuminated on the right side and had a dark shadow on the left side indicating a waxing phase. The light region grew over the surface of the Moon with each subsequent night. The first night’s phase was waxing crescent with over 25 percent of the Moon lit up. The next night, the light had grown to cover more of the Moon as it continued through its waxing crescent phase. On November 10th, the Moon exhibited traits of being at first-quarter or half-moon status because at least 50 percent of its surface was illuminated. In the following nights, the Moon displayed characteristics of waxing gibbous as the light continued to grow across the moon’s surface from right to left. The Moon was nearing closer to the full moon phase on November 14th as only a very small dark shadow was visible on the left side.
The Moon takes 27.3 days (sidereal month) to complete its actual orbit around the Earth. Like the Sun, the Moon rises in the east and sets in the west each day.
