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maksim [4K]
3 years ago
15

At this weekend's soccer game, 20 out of the first 30 people who entered the

Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer:

160

Step-by-step explanation:

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The output of a process is stable and normally distributed. If the process mean equals 23.5, the percentage of output expected t
erastovalidia [21]

Answer:

Option a) 50% of output expected to be less than or equal to the mean.

Step-by-step explanation:

We are given the following in the question:

The output of a process is stable and normally distributed.

Mean = 23.5

We have to find the percentage of output expected to be less than or equal to the mean.

Mean of a normal distribution.

  • The mean of normal distribution divides the data into exactly two equal parts.
  • 50% of data lies to the right of the mean.
  • 50% of data lies to the right of the mean

Thus, by property of normal distribution 50% of output expected to be less than or equal to the mean.

6 0
4 years ago
12 in A 4 in. 1 3 in. 7 in.​
Strike441 [17]
I’m not sure I understand your question
4 0
3 years ago
What is it equal to ?
Anna35 [415]

Answer

D is it no others $$

Step-by-step explanation:

5 0
3 years ago
Need the answer to number 8 pls
Rama09 [41]
We can split it up into

( \frac{x^4+2x^2}{x^2+2})+(  \frac{1}{x^2+2} )= (\frac{x^2(x^2+2)}{x^2+2})+(  \frac{1}{x^2+2} )x^2+\frac{1}{x^2+2}
I see you were supposed to use synthetic division

not sure what the 'related function is'
but as |x| approaches positivie infinity, y approaches positive infinity
as |x| approaches negative infinity, y approaches positive infinity

for the original function
as x approaches positivie infinity x^2+ \frac{1}{x^2+2} approaches positive infinity
as x approaches negative infinity x^2+ \frac{1}{x^2+2} approaches positive infinity
this is due to the x^2 term making it positive
6 0
4 years ago
53% of 80<br> ? What is the percentage?
quester [9]

Answer:

42.4

Hope that this helps!

5 0
3 years ago
Read 2 more answers
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