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3 years ago

Find the perimeter of a rectangle with a base of 24m and a height of 36m.

1 answer:

7 0

To find the perimeter of a rectangle, you need to add the lengths of the rectangles four sides. Since we have the base and the height this is easy. 24 x 2 + 36 x 2 = 120. Hope this helps!

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Answer must be in fraction form

Damm [24]

Answer:

-7/18

Step-by-step explanation:

To multiply fractions, you just multiply the top number by the top number and the bottom number by the bottom number. Also, you have to watch the sign.

In this case, we have a positive fraction multiplied by a negative fraction, meaning that our answer must be negative.

So we have- 2x7 / 4x9.

This is simplified to be- 14/36, or 7/18.

However, the answer is actually -7/18, since the number must be negative.

Let me know if this helps.

8 0

3 years ago

PLEASE HELP!!!!!! I need help on this problem

Thepotemich [5.8K]

Answer:

185 minutes.

Step-by-step explanation:

It is possible to model an equation for this, such that

$0.10x + 14.80 = 0.08x + 18.50$

where x represents the number of minutes.

Then, you solve for x:

$0.10x + 14.80 = 0.08x + 18.50 \\ 0.02x = 3.70 \\ x = \frac{3.70}{ 0.02} \\ x = 185$

5 0

3 years ago

The diameter of circles A,C and E are 32 cm, 24cm and 14 cm respectively

Karolina [17]

Answer:

AG = 4

AH = 21

EC = 12

CH = 5

HE = 7

Step-by-step explanation:

The complete question is

The diameters of circles A, C and E are 32 cm, 24 cm and 14 cm respectively.

Which of the following statements are true? Select all that apply.

•AG = 4

•GC = 10

•AH = 21

•EC = 12

•EH = 5

•CH = 5

•HE = 7

The picture of the question in the attached figure

Verify each statement

1) AG = 4

we know that

$AG=AC-GC$

$AC=32\2=16\ cm$ ----> radius of circle A

$GC=24/2=12\ cm$ ----> radius of circle C

substitute

$AG=16-12=4\ cm$

therefore

The statement is true

2) GC = 10

we know that

$GC=24/2=12\ cm$ ----> radius of circle C

therefore

The statement is false

3) AH = 21

we know that

$AH=AC+CH$

we have

$AC=16\ cm$ ----> radius of circle A

$CH=CE-HE$

$CE=12\ cm$ ----> radius of circle C

$HE=14/2=7\ cm$ ----> radius of circle E

$CH=12-7=5\ cm$

$AH=16+5=21\ cm$

therefore

The statement is true

4) EC = 12

we know that

$EC=24/2=12\ cm$ ----> radius of circle C

therefore

The statement is true

5) EH = 5

we know that

$EH=14/2=7\ cm$ ----> radius of circle E

therefore

The statement is false

6) CH = 5

we know that

$CH=CE-HE$

$CE=12\ cm$ ----> radius of circle C

$HE=14/2=7\ cm$ ----> radius of circle E

$CH=12-7=5\ cm$

therefore

The statement is true

7) HE = 7

we know that

$HE=14/2=7\ cm$ ----> radius of circle E

therefore

The statement is true

3 0

3 years ago

PLEASE HELP IN IMAGE nonsense will be reported

Degger [83]

The answer is -2. The line is going from left to right which makes it negative. Then if you look at the line and do change in y(rise) over change in x(run).

8 0

3 years ago

A cylindrical tank has a radius of 15 ft. and a height of 45 ft. How many cubic feet of water can the tank hold?

vladimir1956 [14]

The formula to solve for this would be pi(r^2)xheight. Essentially what this formula does is it takes the are of the base (pi x r^2) and multiplies it by the height of the cylinder to find how many times the base can stack on itself until it reaches the top. This formula of base are times height works for all prisms with two bases. Here are the steps to solve:

1) plug in the values
- pi(15^2) x 45

2) solve for the base area of one of the circles
- pi(15^2)=225pi

3) multiply the base area by the height
- 225pi x 45 = 10,125pi

4) final answer: the tank can hold 10,125pi cubic feet of water

4 0

4 years ago