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MAXImum [283]
3 years ago
10

Nathan bought a wallet for 5% off its full price. What was the full produce of the wallet if Nathan paid 17.67 before sales tax

A.18.60 B.22.67 C. 17.72 D. 19.53
Mathematics
2 answers:
AfilCa [17]3 years ago
6 0
A. 18.60, because you multiply 18.6 by .05 to get .93, and then subtract .93 from 18.6 to get 17.67.
erastovalidia [21]3 years ago
3 0

Answer:

Option A is correct.

Step-by-step explanation:

Let the full price of the wallet be represented by = x

Total amount that Nathan paid for the wallet = $17.67

Discount percentage = 5% or 0.05 = 0.05x (5% of full price)

So, equation becomes: full price - discount price = 17.67

x-0.05x=17.67

0.95x=17.67

x = $18.60

Therefore, the full price of the wallet is $18.60.

We can also check this by taking out 5% of 18.60

0.05\times18.60=0.93

And18.60-0.93=17.67

So, option A is correct.

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DochEvi [55]
Given:
Budget = $30
cost of pizza = $9
cost of drinks = $1
number of pizza = p
number of drinks = d

pizza and drinks should only be equal to or less than the budget of $30.

$9p + $1d <u>< </u>$30

unit cost of pizza :          9 
unit cost of drinks :         1
total cost of set (p & d) 10

pizza = 9/10 x 30 = 27 total cost of pizza
drinks =1/10 x 30 =   3 total cost of drinks

27 ÷ 9 = 3 number of pizzas to order 
  3 ÷ 1 = 3 number of drinks to order

To check:

9p + 1d <u>< </u>30
9(3) + 1(3) <u>< </u>30
27 + 3 <u>< </u>30
30 <u>< </u>30
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Which values of x are point(s) of discontinuity for this function? Function x = –4 x = –2 x = 0 x = 2 x = 4
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Step-by-step explanation:

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shepuryov [24]

Answer:

Step-by-step explanation:

First equation

x + y ≥ 10

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Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co
jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If \sum a_n is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho

If \rho < 1, the series converges absolutely

If \rho > 1, the series diverges

If \rho = 1, the test fails.

Given the series \sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}

To test for convergence or divergence using ratio test, we will use the condition above.

a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}

\frac{a_n_+_1}{a_n} =  \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\

\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\

aₙ₊₁/aₙ =

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note that any constant dividing infinity is equal to zero

|\frac{1+2/\infty+1/\infty^2}{5}|\\\\

\frac{1+0+0}{5}\\ = 1/5

\rho = 1/5

Since The limit of the sequence given is less than 1, hence the series converges.

5 0
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