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levacccp [35]
3 years ago
13

Whenever a body is in motion, there is always ____ to oppose the motion.

Chemistry
1 answer:
seropon [69]3 years ago
7 0

Answer:

Force

Explanation:

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g Phosphorus -32 is a commonly used radioactive nuclide in biochemical research, particularly in studies of nucleic acids. The h
Setler79 [48]

Answer:

6.88 mg

Explanation:

Step 1: Calculate the mass of ³²P in 175 mg of Na₃³²PO₄

The mass ratio of Na₃³²PO₄ to ³²P is 148.91:31.97.

175 mg g Na₃³²PO₄ × 31.97 g ³²P/148.91 g Na₃³²PO₄ = 37.6 mg ³²P

Step 2: Calculate the rate constant for the decay of ³²P

The half-life (t1/2) is 14.3 days. We can calculate k using the following expression.

k = ln2/ t1/2 = ln2 / 14.3 d = 0.0485 d⁻¹

Step 3: Calculate the amount of P, given the initial amount (P₀) is 37.6 mg and the time elapsed (t) is 35.0 days

For first-order kinetics, we will use the following expression.

ln P = ln P₀ - k × t

ln P = ln 37.6 mg - 0.0485 d⁻¹ × 35.0 d

P = 6.88 mg

3 0
3 years ago
An alloy contains 57 g of silver and 20g of copper what is the percentage silver in the alloy
Allushta [10]
Total weight of alloy is
67 + 20 = 87 g
67 g of which is gold
So % gold is 67/87* 100 = 77.01%
4 0
3 years ago
How much does 0.0273 moles of Na2O weigh
devlian [24]

Answer:

1.69 g Na₂O

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.0273 mol Na₂O

<u>Step 2: Identify Conversions</u>

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol

<u>Step 3: Convert</u>

<u />0.0273 \ mol \ Na_2O(\frac{61.98 \ g \ Na_2O}{1 \ mol \ Na_2O} ) = 1.69205 g Na₂O

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.69205 g Na₂O ≈ 1.69 g Na₂O

6 0
3 years ago
How does the sun compare to other stars
Reptile [31]
By <span>Our </span>sun<span> is a bright, hot ball of hydrogen and helium at the center of our solar system.</span>
5 0
3 years ago
Read 2 more answers
What is T2, if T1= 500 k, v1=10L, V2=8L,P1=600 torr,P2=200 torr?
Molodets [167]

Answer:

T2 = 133.333°K

Explanation:

Using Combined Gas Laws:

(600 torr)(10L)/500°K = (200 torr)(8L)/x°K

\frac{600 torr(10L)}{500K} =\frac{200 torr(8L)}{xK}

Cross multiply:

x°K (600 torr)(10L) = 500°K(200 torr)(8L)

Divide:

x°K = (500°K(200 torr)(8L))/(600 torr)(10L)

xK = \frac{500K(200 torr)(8L)}{600 torr(10L)}

x = 400/3°K or 133.333°K

8 0
3 years ago
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