Question

What is T2, if T1= 500 k, v1=10L, V2=8L,P1=600 torr,P2=200 torr?

Answer 1

Answer:

T2 = 133.333°K

Explanation:

Using Combined Gas Laws:

(600 torr)(10L)/500°K = (200 torr)(8L)/x°K

$\frac{600 torr(10L)}{500K} =\frac{200 torr(8L)}{xK}$

Cross multiply:

x°K (600 torr)(10L) = 500°K(200 torr)(8L)

Divide:

x°K = (500°K(200 torr)(8L))/(600 torr)(10L)

$xK = \frac{500K(200 torr)(8L)}{600 torr(10L)}$

x = 400/3°K or 133.333°K