All categories

3 years ago

Please please help with this. i need all 10 plsss. will mark as brainliest

Mathematics

1 answer:

iren2701 [21]3 years ago

5 0

Answer:

1) (x+3)(x+4)

2) (x-9)(x+1)

3) (x-6)(x+5)

4) (x-3)(x-5)

5) (x-10)(x+1)

6) (x+3)(x+8)

7) (x-2)(x-8)

8) (x+4)(x-1)

9) (x-9)(x+5)

10) (x-8)(x+2)

You might be interested in

Kevin is taking a two-part test in social studies

Phantasy [73]

Answer:

He need to earn 32 points on part 2.

5 0

2 years ago

On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 1), point B is at (3, 2), and points C is at (negativ

oksian1 [2.3K]

The corresponding height of the triangle is 1.6 units

The formula for calculating the area of a triangle is expressed as:

$A=\frac{1}{2} bh$

b is the base of the triangle

h is the height of the triangle

Given the coordinates of the base BC of the triangle given as B(3, 2), and C(-1,-1). Using the distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\BC= \sqrt{(-1-2)^2+(-1-3)^2}\\BC=\sqrt{3^2+4^2}\\BC=\sqrt{25}\\BC=5units$

The area of the triangle passing through the coordinate points A(-1, 1), B(3,2), and C(-1, -1) is expressed as:

$A=\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]\\$

Substituting the coordinate points:

$A=\frac{1}{2}[(-1)(2-(-1))+3(-1-1)+-1(1-2)]\\A=\frac{1}{2}[(-1)(3)+3(-2)+-1(-1)]\\A=\frac{1}{2}[-3-6+1]\\A=\frac{1}{2} (-8)\\|A| =4 units^2$

Recall that:

$A = 0.5bh\\h=\frac{A}{0.5b}\\h=\frac{4}{0.5(5)}\\h=\frac{4}{2.5}\\h= 1.6 units$

Hence the corresponding height of the triangle is 1.6 units

Learn more on area of triangles here: brainly.com/question/17335144

8 0

2 years ago

Diego went out for a walk. He walked for 20 minutes East at a rate of 5km/hour. He then turned around and walked west for 10 min

iVinArrow [24]

Positive 20 and negative 10 is a net amount of 10. 10 minutes is 1/6 of an hour. 5*1/6=5/6km

3 0

3 years ago

How do I solve this

sdas [7]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
\cfrac{2x}{x^2+2x-24}-\cfrac{x}{x^2-36}\quad 
\begin{cases}
x^2+2x-24\implies (x+6)(x-4)\\
--------------\\
x^2-36\implies x^2-6^2\\
(x-6)(x+6)
\end{cases}$

$\bf \cfrac{2x}{(x+6)(x-4)}-\cfrac{x}{(x-6)(x+6)}\impliedby 
\begin{array}{llll}
\textit{thus our LCD is}\\
(x-6)(x+6)(x-4)
\end{array}
\\\\\\
\cfrac{[(x-6)2x]~-~[(x-4)x]}{(x-6)(x+6)(x-4)}\implies \cfrac{2x^2-12x-x^2+4x}{(x-6)(x+6)(x-4)}
\\\\\\
\cfrac{x^2-8x}{(x-6)(x+6)(x-4)}$

3 0

3 years ago

If Joe makes 16 out of 40 free throws in a

abruzzese [7]

The answer would be 6.4% because you have to do 16% of 40 and it will give you 6.4 and as a percent it is 640%

8 0

3 years ago