I am pretty sure the awnser is yes because 2.5 divided by 3 equals .83 repeating which mean for one dozen of cupcakes(12) it would take .84 cups of flour.
Answer:
x > 4
Step-by-step explanation:
7x + 2 > 30
Subtract 2 from each side
7x + 2-2 > 30-2
7x > 28
Divide each side by 7
7x/7 > 28/7
x > 4
Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.
To find : Area (ΔMNC)
Solution: In Δ ABC, right angled at C,
AC= 6 cm, BC= 8 cm
Using pythagoras theorem
AB² =AC²+ BC²
=6²+8²
= 36 + 64
→AB² =100
→AB² =10²
→AB =10
Also, AM:MN:NB=1:2.5:1.5
Then AM, MN, NB are k, 2.5 k, 1.5 k.
→2.5 k + k+1.5 k= 10
→ 5 k =10
Dividing both sides by 2, we get
→ k =2
MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm
As Δ ACB and ΔMNC are similar by SAS.
So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.
![\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}](https://tex.z-dn.net/?f=%5Cfrac%7BAr%28ACB%29%7D%7BAr%28MNC%29%7D%3D%5B%5Cfrac%7B10%7D%7B5%7D%5D%5E%7B2%7D)

But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]

→ Area(ΔMNC)=24÷4
→Area(ΔMNC)=6 cm²
3 hats each is the largest amount Brian can buy
To get this answer I multiplied 3 friends by $5 amount of each hat and got $15 then I divided that into 57$ and got 3.8. So he can only afford to get each friend 3 hats each Brian should have $12 left
Answer:
8. 504ft²
9. 4970yd² (rounded to 3 s.f.)
Formulas (For easy reference):
Area of rectangle = length × breadth
Area of circle = pi×r×r
Circumference of circle = pi×r×2
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Step-by-step explanation:
8. You know a box has 6 sides, and there are 3 types of surfaces that are different from each other, and you have to multiply each side by 2 cus there are the front and backside (You can draw the box with its dimensions to see the 3 types of surfaces and why I multiplied by 2):
(2×12×6) + (2×12×10) + (2×6×10) = 144 + 240 + 120
= 504ft²
9. The net of a cylinder contains two circles of radius 24yd and one long sheet to wrap around the circles with the length that is the circumference of the circle (so that it can wrap around the two circles) and a width which is the height of the cylinder (9yd).
2 Circles = 2×pi×24×24
= 1152pi
Long sheet = 9×24×2×pi
= 432pi
Now we can add all of them together:
432pi+1152pi = 1584pi
= 4970yd² (rounded to 3 s.f.)