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olganol [36]
3 years ago
15

Answer: d Explanation: Hope this helps pzzzz marke brainliest

Mathematics
2 answers:
zhenek [66]3 years ago
3 0
Youre answer is D, you’re welcome
Rudiy273 years ago
3 0

Answer:

lol think you made the wrong thing.

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(Kinda need help ASAP)
denis23 [38]

Answer:

Plzzzz answer fast......

4 0
2 years ago
Translate the sentence into an inequality.
Luda [366]

Answer:

5 + c > -22

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Inequalities

Step-by-step explanation:

<u>Step 1: Define</u>

Sum of 5 and c is greater than -22

↓ <em>Identify</em>

Sum = addition

  • 5 + c

Is greater than = inequality

  • >

Add them all together:

5 + c > -22

8 0
2 years ago
The circumference of a circle is 16Pi ft.<br><br> The radius is <br> ft.
mafiozo [28]
8pi ft

Just divide 16 by 2 because it’s half of the diameter
6 0
3 years ago
If t=0 in 1980, find the value of A. Round answer to the nearest million.
balu736 [363]

P=Ae^kt

225 = 210 * e^(k*(1990-1980)

225/210=e^10k ln(225/210)=10k

k=ln(225/210)/10=0.0069

P = 210*e^(0.0069t)

for 2000 ===> t = 2000-1980=20

P = 210*e^(0.0069*20)

P=241.0749=241

4 0
3 years ago
Part of the proceeds from a garage sale was $470 worth of $10 and $20 bills. If there were 14 more $10 bills than $20 bills, fin
Brums [2.3K]

There are 25 $10 bills and 11 $20 bills.

Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

x be the number of $10 bills

y be the number of $20 bills.

According to given situation;

10x+20y=470       Eqn 1

x = y+14                Eqn 2

Putting value of x from Eqn 2 in Eqn 1

10(y+14)+20y=470\\10y+140+20y=470\\30y=470-140\\30y=330

Dividing both sides by 30

\frac{30y}{30}=\frac{330}{30}\\y=11

Putting y=11 in Eqn 2

x=11+14\\x=25

There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/1279756
  • brainly.com/question/1284310

#LearnwithBrainly

5 0
2 years ago
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