1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
icang [17]
3 years ago
5

Please help I don't understand​

Mathematics
1 answer:
7nadin3 [17]3 years ago
4 0

Answer:

1<x≤8

Step-by-step explanation:

x is greater than one, but is less than or equal to 8

You might be interested in
What is 20.30 - 19.70 and what are the solving steps?
DIA [1.3K]

Answer

0.6

Step-by-step explanation:

here is the working out! Can i get brainliest

5 0
3 years ago
Read 2 more answers
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
Help ASAP
kramer

Answer:

x=19/5

Step-by-step explanation:

x*2+8x=38

10x  =38

5 0
2 years ago
Use the properties of quadrilaterals to complete the statements. A has exactly one pair of parallel sides. A must have two pairs
vesna_86 [32]

Answer:

1. Trapezoid

2. Kite

3. Square, Rhombus

Step-by-step explanation:

Given - Use the properties of quadrilaterals to complete the statements.

To find - A ..... has exactly one pair of parallel sides.

             A ....... must have two pairs of adjacent sides congruent.

             A ........ must have all congruent sides.

Proof -

A Trapezoid has exactly one pair of parallel sides.

A Kite must have two pairs of adjacent sides congruent.

A Square, Rhombus must have all congruent sides.

Reason -

  • A trapezoid is a quadrilateral with exactly one pair of parallel sides.
  • A kite is a quadrilateral with exactly two pairs of adjacent congruent sides.
  • A rhombus is a parallelogram with four congruent sides.
  • A square can be defined as a rhombus which is also a rectangle . In other words, a square is a parallelogram with four congruent sides and four right angles.

5 0
3 years ago
An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

4 0
3 years ago
Other questions:
  • MathWizard likes to play a fun number trick on her friends. She tells them to think of a number. She then tells them to subtract
    10·1 answer
  • Factor completely x2 - 36. I think this is Prime is that correct
    10·2 answers
  • Just trying to get through this class from hell
    5·1 answer
  • Gabriel unfolded a cube to form the net below.
    6·1 answer
  • Anna invested 2500 at an annual rate of 5% how long will it take until Anna earns 1125 in interest
    5·1 answer
  • How many times will the digit '1' appear if we write all whole numbers from 1 to 999?
    13·1 answer
  • Solve. d + 8 &lt; 35<br><br> A d &lt; –27<br> B d &lt; 27<br> C d &lt; –43<br> D d &lt; 43
    10·1 answer
  • Bracelets use 1/4 yard of string and 10 charms. You have 9/10 yards string and 72 charms. If you use all the string what fractio
    14·1 answer
  • Grandma Stella shared her last estate worth $130,000.00 in the ratio of 8:5 between her two children Boyo and Marla respectively
    11·1 answer
  • Could someone help me really quickly :(((((
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!