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rusak2 [61]
3 years ago
12

Cedric can swim a lap in 23 and 3/5 seconds. Jason can swim a lap in21.4 seconds. How much faster can Jason swim in a lap than C

edric?
Mathematics
2 answers:
Nataly [62]3 years ago
7 0
3/5= .6
23 + 0.6= 23.6
23.6- 21.4= 2.2 seconds faster
Setler79 [48]3 years ago
6 0
Jason swims 2.2 seconds faster than cedric
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Runner A completes 12 laps around a track in 22 minutes. Runner B completes 8 laps in 15 minutes. Which runner had a greater ave
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Step-by-step explanation:

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What is the perimeter of the figure in the diagram (round to three decimal places if necessary)? A) 54.5 B) 42.634 C) 39.5 D) 27
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D

Step-by-step explanation:

First add all the simple line up so;

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\sqrt{ {2}^{2}  +  {4}^{2} }   = 2 \sqrt{5}  \\  \sqrt{ {3}^{2}  +  {1}^{2} }  =  \sqrt{10}  \\ 20 +  \sqrt{10}  + 2 \sqrt{5} = 27.63441362

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3 years ago
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
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Answer:

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The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

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3 years ago
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Answer: the median is 69

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