Using a binomial distribution considering there's a 30% chance it will rain on any of the three days:
<span>The probability of it raining on 0 days is (1)(0.7)(0.7)(0.7) = 34.3%. </span>
<span>The probability of it raining on 1 day is (3)(0.3)(0.7)(0.7) = 44.1%. </span>
<span>The probability of it raining on 2 days is (3)(0.3)(0.3)(0.7) = 18.9%. </span>
<span>The probability of it raining on 3 days is (1)(0.3)(0.3)(0.3) = 2.7%. </span>
<span>There's a 65.7% chance that it will rain at least once over the three-day period.</span>
Answer:
1. ∠A and ∠B are right angles. Given
2. m∠A = m∠ B All right angles are congruent.
3. ∠BEC≅ ∠AED Vertical angles are congruent
4. ΔCBE ~ ΔDAE AA
Step-by-step explanation:
A proof always begins with the givens.
1. ∠A and ∠B are right angles. -------------->Given
2. m∠A = m∠ B are equal since-----------> All right angles are congruent.
3. ∠BEC≅ ∠AED are also equal since---->Vertical angles are congruent
4. ΔCBE ~ ΔDAE since two angles are equal----------> AA
Answer: The probability is 2/5.
Step-by-step explanation: If there are 5 pink bows, 1 blue bow, and 4 purple bows, there are a total of 10 bows in the box. The probability of choosing a purple one is 4/10 (since there are 4 purple bows). 4/10 simplifies to 2/5.
Adding a positive to a negative, you would look at the number with the greater absolute value, and that number would determine the sign of the sum.
5 - 3 = 2
Since 5 is bigger, you use that sign
-5
-2
Answer: -2
