Umm helppppppppppppppp

Is 2.389746 rational or irrational

Nina [5.8K]

Answer:

it's rational

Step-by-step explanation:

6 0

3 years ago

If f(x) = x³ + x, find <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh%7D%2C%20f%5Cneq%200" id="TexForm

Snowcat [4.5K]

I think you are doing limits so this is what I did
and that's how I factored using the box method because it's easier to track distribution.

6 0

3 years ago

There are a total of 72 students in a drama club and a yearbook club. The drama club has 12 more students than the yearbook club

svetlana [45]

VARIABLES:
[x] Yearbook Club (expression: x)
[y] Drama Club (expression: x + 12)

EQUATIONS:
#1 x + y = 72
#2 y = x + 12

Now we shall use the method of substitution to solve.

FINDING X:
#1 x + (x + 12) = 72
#2 2x + 12 = 72
#3 2x = 60
#4 x = 30

The amount of students in the yearbook club: 30
The amount of students in the drama club: 72 - 30 = 42

If you can, please give me brainliest. Thank you!

5 0

3 years ago

Raj's company ships T-shirts in boxes shaped like cubes. The picture below shows the cube

Rzqust [24]

Answer: The surface area of each cube is 24 ft² (24 square feet)

Step-by-step explanation: The boxes according to the question are shaped like cubes, which means the shape we have here has square faces on all sides. Also the boxes have been opened up into nets and this shows each box as having 6 faces.

The area of each face is derived as follows;

Area = L x W

Area = 2 x 2

Area = 4 ft²

Having calculated the surface area of each face, a box or cube with 6 faces will have its surface area as;

Area of box = Face area x 6

Area of box = 4 x 6

Area of box = 24 ft²

Therefore in designing labels for all of the boxes, Raj would need 24 square feet of label for each box.

8 0

3 years ago

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(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.

DaniilM [7]

Answer:

The answer is " $\frac{2}{9} \ and \ \frac{1}{9}$ "

Step-by-step explanation:

In point a:

The requires 1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They can pick 1 Chunin form of the matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They have the option to pick 1 join from of the country team with such a probability: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

And we can make the country teams: $3! = 6$ different forms. Its chances of choosing a team full in the process described also are:

$6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.$

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

Its odds of choosing the same rank ninja in such a different country team are: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

The likelihood of choosing the same level Ninja from the residual matter of national is: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$ Therefore, all 3 selected ninjas are likely the same grade: $3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}$

4 0

3 years ago

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