Adding the numbers gives us a total of 65
Jan = 20/65 = 30.7% = 31%
Feb = 25/65 = 38.4% = 38%
Mar = 1/65 = 1.5% = 2%
Apr = 3/65 = 4.6% = 5%
May = 16/65 = 24.6% = 25%
I believe ur answer is 30%
Answer:
The product is:
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
For this problem you need to multiply the first row only for the two first column of the others matrix and get the desired result:
![\left[\begin{array}{ccc}1&3&1\\-2&1&0\end{array}\right] \times \left[\begin{array}{cc}2&-2\\3&5\\4&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%263%261%5C%5C-2%261%260%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%265%5C%5C4%261%5Cend%7Barray%7D%5Cright%5D)

So the value of the element in the position
is 15

So the value of the element in the position
is 14
Then with these two values you can determinate the result matrix.
![\left[\begin{array}{cc}15 & 14\\-1 & 9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D15%20%26%2014%5C%5C-1%20%26%209%5Cend%7Barray%7D%5Cright%5D)
Hmmm idk if you want fractions but, 65/24 or 2 17/24 I think
You just need to list the equations of the two graphs.
y=x^2 + 2
y=x+4
Answer:
option C
y = 2
Step-by-step explanation:
Given in the question,
a co-ordinate = (-2,2)
x = -2
y = 2
Equation of the straight line
y = mx + c
<em>here m = gradient of the line</em>
<em> c = y - intercept</em>
<em />
<h3>we know that gradient of the horizontal line = 0</h3>
plug value in the equation above
y = (0)x + 2
y = 2