A study shows that employees who begin their workday at 9:00 a.m. vary their times of arrival uniformly from 8:40 a.m. to 9:30 a
1 answer:
Answer:
0.2 or 20%
Step-by-step explanation:
If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.
The range between 8:40 and 9:30 is 50 minutes.
The range between 9:00 and 9:10 is 10 minutes.
Therefore, the probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:
The probability is 0.2 or 20%.
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9514 1404 393
Answer:
x -y = -5
3x +y = -11
Step-by-step explanation:
We assume you want two linear equations. Since you know a point on each line, the only thing you need to choose is the slope of the two lines through that point. We can make the slopes be +1 and -3, for example. Then the point-slope equations are ...
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
y -1 = +1(x +4)
y -1 = -3(x +4)
We can use these equations "as is", or put them in whatever form you like. I personally prefer "standard form:" ax+by=c.
<u>First equation</u>:
y -1 = x +4 . . . . . . eliminate parentheses
-5 = x -y . . . . . . . keep positive x term, put x and y together, separate from the constant
x - y = -5 . . . . . . standard form
<u>Second equation</u>:
y -1 = -3x -12 . . . . eliminate parentheses
3x +y = -11 . . . . . . add 3x+1 to both sides
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A system of equations with solution (-4, 1) is ...
- x - y = -5
- 3x + y = -11
