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noname [10]
3 years ago
9

In how many ways can you arrange MATHEMATICS if duplication of the arrangement are not allowed?​

Mathematics
1 answer:
sukhopar [10]3 years ago
7 0

Answer:

4989600 ways

Step-by-step explanation:

From the question,

The word MATHEMATICS can be arranged in n!/(r₁!r₂!r₃!)

⇒ n!/(r₁!r₂!r₃!) ways

Where n = total number of letters, r₁ = number of times M appears r₂ = number of times A appears, r₃ = number of times T appears.

Given: n = 11, r₁ = 2, r₂ = 2, r₃ = 2

Substitute these value into the expression above

11!/(2!2!2!) = (39916800/8) ways

4989600 ways

Hence the number of ways MATHEMATICS can be arranged without duplicate is 4989600 ways

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If LP = 15 and PR = 9, find LR. Explain.
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Answer:

24

Step-by-step explanation:

LP = 15 on one side

LR= 9 on the other side

____________________|____________|

 P                                      L                            R

add them and PR is 24

15+9= 24

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Find the distance between the given point (2,-2) and (-4,-7)
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Step-by-step explanation:

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A plane can carry a maximum cargo weight of 160,000 pounds. A company uses one of these
Svetlanka [38]
They can carry 80 containers each
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6 0
3 years ago
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dezoksy [38]

Answer:

Round 1.9 to 2 cm and multiply by 18.

Step-by-step explanation:

Round 1.9 to 2 cm and multiply by 18. then you will get your answer

8 0
3 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
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